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2 years ago

9-12 Use the properties of logarithms to expand the quantity.

Mathematics

1 answer:

Sever21 [200]2 years ago

3 0

Step-by-step explanation:

lnx² - lny³ - lnz⁴

2lnx - 3lny -4lnz

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On-the-Go Phone Company has two monthly plans for their customers.The EZ Pay Plan costs $0.15 per minute. The 40 to Go Plan cost

natulia [17]

For one moth it would be....
$30 + 40 + 0.05$
$57.00 In total but im not sure if this is correct so if you could make sure please.

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3 years ago

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A cube has a volume of 64 cubic meters what is the length of each edge

Murljashka [212]

Answer:

The length of each side is 4 m

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

64 = s^3

Take the cube root of each side

64 ^ (1/3) = s^3 ^ (1/3)

4 = s

The length of each side is 4 m

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3 years ago

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Graph and check to solve the linear system <br> x+y=3<br> -2x+y=-6

Alenkinab [10]

Answer:

-x - y = -3

-2x + y = -6

-3x = -9

x = 3

3 + y = 3

y = 0

(3,0)

6 0

2 years ago

I need help please and thank you

myrzilka [38]

Answer:

Step-by-step explanation:

Slope = y2- y1/ x2- x1

= 4 - (-2) / 3 -1

= 4+2/ 2

=6/2 = 3

4 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago