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irina [24]
3 years ago
11

Give f(x)=4x-6 and g(x)=f(2x), write an equation for g

Mathematics
1 answer:
neonofarm [45]3 years ago
7 0

Step-by-step explanation:

G(x) =4(2x)-6

G(x)=8x-6

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Vat is 2+5+5+5-2
vodka [1.7K]

Answer:

Your answer is 15

Step-by-step explanation:

2+5= 7

7+5= 12

12+5=17

17-2= 15

6 0
3 years ago
A right triangle has one leg that is 12 units long and a hypotenuse that is 15 units long. Find the length of the other leg
mina [271]
Let a be the <span>other leg.
</span>
By the Pythagorean theorem:

a= \sqrt{15^2-12^2}= \sqrt{225-144}= \sqrt{81}=9 \ units
4 0
3 years ago
Read 2 more answers
Pls help asap...urgently help needed!!!<br>tia
ziro4ka [17]

Answer:

(a) v =  1536640/ m^2.

(b)  (i)   1186 m/s.

     (ii)   52.4g .

Step-by-step explanation:

(a)   The equation is v = k / m^2     where k is the constant of variation.

When m = 49, v = 640 so   640 = k / 49^2

k = 640 * 49^2

= 1,536,640.

Therefore the relation is v =  1536640/ m^2.

(b) (i)

When m = 36g,  the speed v = 1536640 / 36^2

= 1186 m/s.

(ii)   When the speed is  560 m/s :-

560 = 1536640 / m^2

m^2 = 1536640 / 560

=  2744

mass m = √2744

=  52.4g  

3 0
3 years ago
Show your work for the math problem
faltersainse [42]

X + 2x -20 = 85

Combine like terms:

3x -20 = 85

Add 20 to both sides:

3x = 105

Divide both sides by 3

X = 35

8 0
3 years ago
Read 2 more answers
While constructing an equilateral triangle or a regular hexagon inscribed in a circle, you may have noticed that several smaller
Sauron [17]

Answer:

Using the transitive property of geometry, we proved that △PQR is an equilateral triangle.

Step-by-step explanation:

The diagram of the given scenario is in the attachment.

Here, PQ is the radius of circle Q

Also, PQ is the radius of circle P

Hence, circle-P and circle-Q have same radii.

Now, PQ=RQ as both are radii of circle Q

And PQ=PR, as both are radii of circle P

Hence as per transitive property, which states that, if any two angles, lines, or shapes are congruent to a third angle, line, or shape respectively, then the first two angles, lines, or shapes are also congruent to the third angle, line, or shape

PR=QR

Now, PQ = QR = PR

Hence, ∆PQR is equilateral.

For more explanation, refer the following link:

brainly.com/question/27884420

#SPJ10

3 0
2 years ago
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