3-y/2=1
-3 -3
-y/2=-2
x2 x2
-y=-4
/-1 /-1
Y=4
Answer:
can yhu see the answer i put?
Step-by-step explanation:
We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
Answer:
8h + g
Step-by-step explanation
When you say "4h2", do you mean 4h multiplied by 2?
If so, then 4h2 = 8h, and 8h+g would be your answer.
Hope this helps :)
