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3 years ago

I WILL GIVE BRANLIEST

Mathematics

2 answers:

Anettt [7]3 years ago

6 0

Answer:C

Step-by-step explanation:

I think it is that because as you see you can see that there are both going different way.

Mrrafil [7]3 years ago

3 0

Answer:

Always increasing

Step-by-step explanation:

The slope of the line is always positive

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What is the simplified expression for -3cd-d(2c-4)-4d

kodGreya [7K]

Answer:

-5cd

Step-by-step explanation:

-3cd-d(2c-4)-4d

Distribute the -d

-3cd-d2c-+d4-4d

-3cd -2cd +4d-4d

Combine like terms

-5cd

4 0

3 years ago

Can somebody please help me???

Nina [5.8K]

Answer:

Answer is option a and b and d

Step-by-step explanation:

Tomas needs exactly 12 potatoes to make 24 potato pancakes
Tomas needs exactly 18 potatoes to make 36 pancakes
Tomas need exactly 30 potatoes to make 60 pancakes
Option a and b and d are correct

Because 12 is twice aa 6

24 is twice as 12

36 is twice as 18

60 is twice as 30

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

3 0

4 years ago

How can you prove that csc^2(θ)tan^2(θ)-1=tan^2(θ)

Oxana [17]

Answer:

Make use of the fact that as long as $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ :

$\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$ .

$\displaystyle \csc(\theta) = \frac{1}{\sin(\theta)}$ .

$\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ .

Step-by-step explanation:

Assume that $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ .

Make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ and $\csc(\theta) = (1) / (\sin(\theta))$ to rewrite the given expression as a combination of $\sin(\theta)$ and $\cos(\theta)$ .

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \left(\frac{1}{\sin(\theta)}\right)^{2} \, \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} - 1 \\ =\; & \frac{\sin^{2}(\theta)}{\sin^{2}(\theta)\, \cos^{2}(\theta)} - 1\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1\end{aligned}$ .

Since $\cos(\theta) \ne 0$ :

$\displaystyle 1 = \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)}$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1 \\ =\; & \frac{1}{\cos^{2}(\theta)} - \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

By the Pythagorean identity, $\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ . Rearrange this identity to obtain:

$\sin^{2}(\theta) = 1 - \cos^{2}(\theta)$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

Again, make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ to obtain the desired result:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\\ =\; & \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} \\ =\; & \tan^{2}(\theta)\end{aligned}$ .

5 0

2 years ago

Which steps could be part of the process in algebraically solving the system of equations, y + 5x = x2 + 10 and y = 4x – 10? Sel

dolphi86 [110]

Answer:

That would be :

4x – 10 = x2 – 5x + 10 ( y = 4x - 10 is substitute for y)

PROOF: y + 5x = x² + 10

(4x - 10) + 5x = x² + 10

4x - 10 = x² -5x + 10

0 = x2 – 9x + 20 (liked terms are grouped and simplified)

PROOF: 4x - 10 = x² -5x + 10

4x = x² -5x + 10 + 10

0 = x² -5x -4x + 20

0 = x² - 9x + 20

Solving:

x² - 9x + 20 = 0

x² - 5x - 4x + 20 = 0

(x - 5) (x - 4) = 0

⇒ x = 4 (as question says) OR x = 5

Step-by-step explanation:

hope this helps

8 0

3 years ago

Read 2 more answers

HELP PLZ TIMED TEST 10 ponits

Archy [21]

Answer:

4... hope this will help

Step-by-step explanation:

5 0

3 years ago