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Agata [3.3K]
3 years ago
6

Don Alfredo quiete construir un corral cuadrado para sus gallinas, utizando metros de malla lineal para redearlo. Si el Zootecni

sta le recomendó construir uno que tenga 121 metros cuadrados. ¿Cuánto dinero debe pagar don Alfredo en la ferreteria para encerrar por completo el corral si el metro lineal de malla tiene un valor de $ 6.200 el metro?
Mathematics
1 answer:
konstantin123 [22]3 years ago
8 0

Answer:

Don Alfredo debe pagar $272,200 para encerrar por completo el corral.

Step-by-step explanation:

Dado que Don Alfredo quiere construir un corral cuadrado para sus gallinas, utilizando metros de malla lineal para rodearlo, si el zootecnista le recomendó construir uno que tenga 121 metros cuadrados, para determinar cuánto dinero debe pagar don Alfredo en la ferretería para encerrar por completo el corral si el metro lineal de malla tiene un valor de $ 6.200 el metro se deben realizar los siguientes cálculos:

121 metros cuadrados = √121 = 11 (x 11) = 11 x 4 = 44 metros lineales

44 x 6,200 = X

272,800 = X

Por lo tanto, Don Alfredo debe pagar $272,200 para encerrar por completo el corral.

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without actually performing the long division state whether 17 / 3125 will have a terminating decimal expansion or a non-termina
baherus [9]

Answer:

It is terminating decimal expansion.

Step-by-step explanation:

17/3125 is a terminating decimal expansion.

REASON:

If the factors of the denominator are in the form of 2^n 5^m then the rational number is a terminating decimal expansion otherwise it is recurring. Here n and m are non negative integers.

Proof:

Lets have a look on the solution of the given term.

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We will break the denominator in the factors:

If we multiply 5 five times than it will give us 1325.

17/1325 = 17/5^5 * 2^0 = 17/2^0 * 5^5

We know that any number with exponent zero = 1

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Answer:

Solution (1.8,1.61)

Step-by-step explanation:

Let us do it one by one.

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y=-3x+7

Let us find some random coordinates to graph this equation

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(0,7)

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(1,4)

Plotting these coordinates on graph , and joining them will give us the line on the graph.

Graph 2 :

y = Sqrt ( 2x-1)

let us find random cordinates for some values of x

x=1, y = sqrt (2(1)-1) = sqrt (1) = 1

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Hence we have two coordinates , now we also see that , after comparing it from standard form of an square root function,

the square root function is upper half of parabola opening towards right and the point of origin is (0.5,0)

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solving it with quadratic formula

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we get x  = 1.8 and replacing it in first equation we get y = 1.61

Hence the solution will be (1.8,1.61)

7 0
3 years ago
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