All categories

3 years ago

What would be the total number of outcomes in the sample space?

Mathematics

2 answers:

snow_tiger [21]3 years ago

8 0

20x26=520

The answer is D 520.

Hope it helps.

shusha [124]3 years ago

4 0

I believe the answer is d 520

You might be interested in

Jack and Julio each improved their yards by planting daylilies and geraniums. They bought their supplies from the same store.

o-na [289]

Cost of one daylily is $2 and cost of one geranium is $4.

Step-by-step explanation:

Let,

Cost of one daylily = x

Cost of one geranium = y

According to given statement;

x+5y=22 Eqn 1

13x+y=30 Eqn 2

From Eqn 1;

x=22 - 5y

Putting this value of x in Eqn 2;

$13(22-5y)+y=30\\286-65y+y=30\\-64y=30-286\\-64y=-256$

Dividing both sides by -64

$\frac{-64y}{-64}=\frac{-256}{-64}\\y=4$

Putting y=4 in Eqn 1

$x+5(4)=22\\x+20=22\\x=22-20\\x=2$

Cost of one daylily is $2 and cost of one geranium is $4.

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

4 0

3 years ago

Under what circumstance should the decision of a significance test be "fail<br> to reject"? *

lbvjy [14]

Answer:

When the calculated value of the test statistics doesn't fall on the critical region.

4 0

3 years ago

Jonah deposited $80 in a savings account earning 5% interest, compounded annually. To the nearest cent, how much interest will h

Katarina [22]

$13 i think would be the answer

3 0

3 years ago

Joline is solving the equation 0 = x2 – 5x – 4 using the quadratic formula. Which value is the negative real number solution to

katen-ka-za [31]

Answer:

- 0.7

Step-by-step explanation:

We are given the general quadratic formula, as " $x = -b \frac{+}{-} \sqrt{(b^2-4ac)} / 2a$ . " This can be represented by two separate formula's, which will come in handy when determining the positive and negative roots of the equation ( and here we need the negative root ):

1 ) $x = - b+ ( \sqrt{b^2-4ac} ) / 2a$ ,

2 ) $x = - b- ( \sqrt{b^2-4ac} ) / 2a$

We know that a = 1, b = - 5, and c = - 4 from the equation " $0 = x^2 - 5x - 4$ " ( which can be rewritten in the form $0 = ax^2 + bx + c$ ). Therefore, simply plug in these values into the quadratic formula to receive two solutions:

$x = 5 + ( \sqrt{( - 5 )^2 - 4( 1 )( - 4 )} ) / 2( 1 ),\\x = 5 + ( \sqrt{25 + 16} ) / 2,\\x = 5 + \sqrt{41} / 2,\\x = ( About ) 5.7$ - This is our positive solution

__________

$x = 5 - ( \sqrt{( - 5 )^2 - 4( 1 )( - 4 )} ) / 2( 1 ),\\x = 5 - ( \sqrt{25 + 16} ) / 2,\\x = 5 - \sqrt{41} / 2,\\x = ( About ) - 0.7$ - And this is our negative solution

You can see that - 0.7 is the negative real number solution to Joline's quadratic equation!

4 0

3 years ago

Fully simplify using only positive exponents.<br> 8x²y<br> x7y5

Bingel [31]

Answer:sorry can't answer that :(

8 0

3 years ago