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Damm [24]
3 years ago
13

Need help with khan, again.

Mathematics
1 answer:
IrinaK [193]3 years ago
5 0

Answer:

6.28

Step-by-step explanation:

1/2 x 3.14 x 2^2 = 6.28

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4.Given w(x) =3×-2, v(x) =2×+7 and k(x)= -6x-7, find (w-v-k) (2)?​
Ivan

Answer:

12

Step-by-step explanation:

We input 2 into each function:

w(2) = 3(2) - 2 = 4

v(2) = 2(2) + 7 = 11

k(2) = -6(2) - 7 = -19

Then we place our answers in w - v - k

(4) - (11) - (-19)

= 4 - 11 + 19

= 12

3 0
3 years ago
Read 2 more answers
Write as a single power of 8.<br> 8 to the power of 8<br><br> ÷<br> 8 to the power of 2
OLEGan [10]

Answer: 8^6

Step-by-step explanation:

\frac{8^8}{8^2} =    8^{6}  subtract the bottom exponent from the top exponent.

7 0
3 years ago
Find the range of allowable values based on an expected mass of 250 grams for which values are allowed to vary by 5%
PIT_PIT [208]

Answer:

woooooooooooooooooooooo

Step-by-step explanation:

wooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

4 0
2 years ago
Write a formula for the general term or nth term for the sequence. Then find the indicated term. five halves comma five fourths
nadya68 [22]
Sequence: 5/2, 5/4, 5/8, 5/16
a8=?

a1=5/2
a2=5/4
a3=5/8
a4=5/16

a2/a1=(5/4)/(5/2)=(5/4)*(2/5)=(5*2)/(4*5)=2/4=1/2
a3/a2=(5/8)/(5/4)=(5/8)*(4/5)=(5*4)/(8*5)=4/8=1/2
a4/a3=(5/16)/(5/8)=(5/16)*(8/5)=(5*8)/(16*5)=8/16=1/2
Ratio: r=a2/a1=a3/a2=a4/a3→r=1/2

an=a1*r^(n-1)
a1=5/2, r=1/2
an=(5/2)*(1/2)^(n-1)
an=(5/2)*[1^(n-1)/2^(n-1)]
an=(5/2)*[1/2^(n-1)]
an=(5*1)/[2*2^(n-1)]
an=5/2^(1+n-1)
an=5/2^n

n=8→a8=5/2^8
a8=5/256

Answers:
The formula for the general term or nth term for the sequence is an=5/2^n
a8=5/256
6 0
3 years ago
Guys please help me whit this , I got a lot of time doing this please give me the answer
Usimov [2.4K]

Answer:

c

Step-by-step explanation:

this needs evaluation of Bella's income on every chore.

say when c = 1, d = 3.5*1+11= 14.5

c=2 d = 3.5*2+11= 18..evaluate for c=3,4,5.

with that it can be found that bella earns more than sweet t. so choice c

8 0
3 years ago
Read 2 more answers
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