S + g = 350; /*(-3) => -3s - 3g = -1050;
3s + 5g = 1450;
=> 2g = 400 => g = 200 ( general admission tickets);
=> s = 350 - 200 => s = 150 ( student tickets);
<h2>
Hello!</h2>
The answer is:
If six sacks are to be taken at a time, the weight of each sack should be at most 308 pounds.
<h2>
Why?</h2>
To calculate the weight that each sack should have, we first need to calculate how many pounds of the elevator capacity are free after is on it.
We know that Kevin weighs 150 pounds and the capacity of the elevator is 2000 pounds, so, calculating we have:
![AvailableCapacity(pounds)=2000pounds-KevinWeighs=2000pounds-150pounds\\\\AvailableCapacity(pounds)=2000pounds-150pounds=1850pounds](https://tex.z-dn.net/?f=AvailableCapacity%28pounds%29%3D2000pounds-KevinWeighs%3D2000pounds-150pounds%5C%5C%5C%5CAvailableCapacity%28pounds%29%3D2000pounds-150pounds%3D1850pounds)
Now that we already know that there are 1850 pounds left to take the delivering sacks, we need to divide it by the number of sacks that need to be taken at a time, so:
![Weight=\frac{1850pounds}{Sacks}=\frac{1850pounds}{6}=308.33pounds](https://tex.z-dn.net/?f=Weight%3D%5Cfrac%7B1850pounds%7D%7BSacks%7D%3D%5Cfrac%7B1850pounds%7D%7B6%7D%3D308.33pounds)
So, we have that if six sacks are to be taken at a time, the weight of each sack should be at most 308 pounds.
Have a nice day!
You would multiply 200 by 40% (0.40 after making it a decimal) then add that to the original cost (200+80=280). Then multiply 280 by 25% (0.25 after making it s decimal) then subtract because it is a discount (280-70=210)