Answer:
A)
Note that
Lower Bound = X - z(alpha/2) * s / sqrt(n)
Upper Bound = X + z(alpha/2) * s / sqrt(n)
where
alpha/2 = (1 - confidence level)/2 = 0.025
X = sample mean = 1723.4
z(alpha/2) = critical z for the confidence interval = 1.959963985
s = sample standard deviation = 89.55083319
n = sample size = 30
Thus,
Lower bound = 1691.355235
Upper bound = 1755.444765
Thus, the confidence interval is
( 1691.355235 , 1755.444765 ) [ANSWER]
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b)
We assumed taht the distirbution of these observations is approximately normally distributed.
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c)
Yes, because the values are not far away from each other.
Answer: 55cm + X*4cm < Y.
Step-by-step explanation:
The initial height of the tree is 55cm
The tree will grow 4cm per month, for X months.
then the height of the tree is the initial height, plus X times 4cm
H = 55cm + X*4cm
If Y is the maximum height that this tree can grow, then we can write the inequality as:
H < Y.
55cm + X*4cm < Y.
Answer:
Step-by-step explanation:
One of the solutions is to graph it and get coordinates of its intersection with the x- axis.
<em>See the graph attached below.</em>
As you see the entire graph is above the x-axis. It means there are no real roots.
Hello,
Answer D (x>17)
6x-8>4x+26
==>6x-4x>26+8
==>2x>34
==>x>17
We have that
<span>question 1
Add or subtract.
4m2 − 10m3 − 3m2 + 20m3
=(4m2-3m2)+(20m3-10m3)
=m2+10m3
the answer is the option
</span><span>B: m2 + 10m3
</span><span>Question 2:
Subtract. (9a3 + 6a2 − a) − (a3 + 6a − 3)
=(9a3-a3)+(6a2)+(-a-6a)+(-3)
=8a3+6a2-7a-3
the answer is the option
</span><span>B: 8a3 + 6a2 − 7a + 3
</span><span>Question 3:
A company distributes its product by train and by truck. The cost of distributing by train can be modeled as −0.06x2 + 35x − 135, and the cost of distributing by truck can be modeled as −0.03x2 + 29x − 165, where x is the number of tons of product distributed. Write a polynomial that represents the difference between the cost of distributing by train and the cost of distributing by truck.
we have that
[</span>the cost of distributing by train]-[the cost of distributing by truck]
=[−0.06x2 + 35x − 135]-[−0.03x2 + 29x − 165]
<span>=(-0.06x2+0.03x2)+(35x-29x)+(-135+165)
=-0.03x2+6x+30
the answer is the option
</span><span>C: −0.03x2 + 6x + 30
</span><span>
</span>