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2 years ago

The black graph is the graph of

Mathematics

1 answer:

Artyom0805 [142]2 years ago

4 0

Answer:

The answer on acellus is d

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What’s the exponent ion regression equation for hat first these data.

Fittoniya [83]

the answer is in the picture

5 0

3 years ago

What values of b satisfy 3(2b + 3)^2 = 36?

goldfiish [28.3K]

3(2b + 3)² = 36

Divide both sides by 3.

3(2b + 3)² / 3 = 36/3

(2b + 3)² = 12

Take the square root of both sides.

√(2b + 3)² = √12

(2b +3) = +√12 or -√12

Solving when:

2b + 3 = +√12 2b + 3 = -√12

2b = √12 - 3 2b = -√12 - 3

b = (√12 - 3)/2 √12 ≈ 3.46 b = (-√12 - 3)/2

b ≈ (3.46 - 3)/2 b ≈ (-3.46 - 3)/2

b ≈ 0.46/2 b ≈ -6.46/2

b ≈ 0.23 b ≈ -3.23

Therefore b ≈ 0.23 or -3.23

Hope this helps.

5 0

4 years ago

For a craft project, four students each chose three pieces of wire from a box. Don's wires measure 3 inches, 5 inches, and 12 in

TiliK225 [7]

Answer:

Sonji's wires measure will be chosen

Step-by-step explanation:

Given:

Don's wires measure = 3 inches, 5 inches, and 12 inches

Margo's wires measure = 6 inches, 8 inches, and 14 inches

Sonji's wires measure = 12 inches, 8 inches, and 17 inches

Liam's wires measure = 16 inches, 8 inches, and 27 inches.

Find:

Measure used to construct a triangle

Computation:

In a triangle sum of two smaller side is grater then bigger side

a + b > c

So.

Don's wires measure = 3 inches + 5 inches < 12 inches

Margo's wires measure = 6 inches + 8 inches = 14 inches

Sonji's wires measure = 12 inches + 8 inches > 17 inches

Liam's wires measure = 16 inches + 8 inches < 27 inches.

So,

Sonji's wires measure will be chosen

6 0

3 years ago

A polygon has vertices A(3, 3), B(3, 6), and C(9, 3). Find the area of the polygon. NEED IT ASAP

avanturin [10]

<h3>Answer: 9 square units</h3>

Explanation:

The diagram is shown below.

Side AC is the base which is 6 units long (since 9-3 = 6)

Side AB is the height which is 3 units

area = base*height/2 = 6*3/2 = 18/2 = 9

3 0

2 years ago

What transformation matrix would result in a 300 degrees counterclockwise rotation about the origin?

Alecsey [184]

For rotation by an angle, θ, in the counter-clockwise direction about the origin, the transformation matrix is given by
$\begin{pmatrix}cos\:\theta &-sin\:\theta \\ sin\:\theta &cos\:\theta \end{pmatrix}$

The given angle is θ=300°.

The values we need are
$cos\left(300^{\circ} \right)=\frac{1}{2}$
$sin\left(300^{\circ} \right)=-\frac{\sqrt{3}}{2}$

Substituting these into the given transformation matrix, we have
$\begin{pmatrix}\frac{1}{2}&\frac{\sqrt{3}}{2}\\ -\frac{\sqrt{3}}{2}&\frac{1}{2}\end{pmatrix}$

4 0

4 years ago

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