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Thepotemich [5.8K]
3 years ago
6

Tell whether the angles are adjacent or vertical. Then find the value of x.

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

adjacent, x=15

Step-by-step explanation:

the angels are connected so they are adjacent, the red box shows that it is a 90 degree angle so adding both angels together means 90=6x so x=15

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A squared+ b squared=????​
Degger [83]

Answer:

<h2>a × a + b × b</h2>

<u>Step-by-step explanation:</u>

= a² + b²

= a × a + b × b

4 0
3 years ago
Find the intercept of g(n)=-2(3n-1)(2n+1)
vaieri [72.5K]
To find the intercepts of this give function of g(n), we have to find both the points present on the axis. That is, X-Intercept axial or axis point and the Y-Intercept axial or axis point and apply the zero factor principle to get the actual points on the graph for both the respective intercepts. Let me make it simpler, by showing the whole process via the LaTeX interpreter equation editor.

The X-Intercept is that actual point present in the graphical interpretation where the Y-axis is taken as zero, this makes us to point out the position of X-Intercept points on its X-axis and Y-axis. Take the variable "n" as the variable of "x", it will not change any context or such, we can take any variables for calculations, it does not hinder the processing of Intercepts for the axial points on a graph.

\boxed{\mathbf{\therefore \quad -2(3x - 1)(2x + 1) = 0}}

By the zero factor principle, both of them can be separately calculated as a zero on their either sides of the expression.

\mathbf{\therefore \quad 3x - 1 = 0}

\mathbf{3x - 1 + 1 = 0 + 1}

\mathbf{3x = 1}

\mathbf{\dfrac{3x}{3} = \dfrac{1}{3}}

\mathbf{\therefore \quad x = \dfrac{1}{3}}

Similarly, for the second X-Intercept point for the value of 0 in the Y-axis or Y axial plane in a 2 dimensional Graphical representation is going to be, As per the zero factor principle:

\mathbf{\therefore \quad 2x + 1 = 0}

\mathbf{2x + 1 - 1 = 0 - 1}

\mathbf{2x = - 1}

\mathbf{\dfrac{2x}{2} = \dfrac{- 1}{2}}

\mathbf{\therefore \quad x = -\dfrac{1}{2}}

Then the X-Intercept here becomes with our provided points as:

\boxed{\mathbf{\underline{X-Intercept: \quad \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg)}}}

Therefore, for our Y-Intercept axial point the X axial plane will instead turn out to be a value with zero on a Graphical representation to obtain the actual points for Y-axis and the Y-Intercept for x = 0 as a point on the graph itself.

Just substitute the value of "0" in "x" axis as a variable on the provided expression. Therefore:

\boxed{\mathbf{= -2(3 \times 0 - 1) (2 \times 0 + 1)}}

\mathbf{y = - 2 (0 - 1) (0 + 1)}

\mathbf{y = - 2 (- 1) (0 + 1)}

\mathbf{y = - 2 (- 1) \times 1}

\mathbf{y = 2 \times 1 \times 1}

\mathbf{\therefore \quad y = 2}

Then, the Y-Intercept would definitely be as per the X-axis lying on the point of zero.

\boxed{\mathbf{\underline{Y-Intercept: \quad \big(0, \: 2 \big)}}}

The final coordinating points for X-Intercept and Y-Intercept for their X-axis and Y-axis will be.

\boxed{\mathbf{\underline{X \: Intercepts: \: \: \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg); \: \: Y \: Intercepts: \: \: \big(0, \: 2 \big)}}}

Hope it helps.
6 0
4 years ago
What type of number is -84/4? <br><br>whole<br>integer<br>rational​
Advocard [28]
Integer -84/4 = -22 which is an integer.
5 0
3 years ago
Read 2 more answers
Can you show us how to find the discriminant of the quadratic x^2 + 2x -2 =0
lorasvet [3.4K]
<em>Step #1: </em>
Make sure the equation is in the form of [ Ax² + Bx + C = 0 ].

Yours is already in that form.
A = 1
B = 2
C = -2

<em>Step #2:</em>
The 'discriminant' for that equation is [ B² - 4 A C ].
That's all there is to it, but it can tell you a lot about the roots of the equation.

-- If the discriminant is zero, then the left  side of the equation is a perfect square,
and both roots are equal. 

-- If the discriminant is greater than zero, the the roots are real and not equal.

-- If the discriminant is less than zero, then the roots are complex numbers.

The discriminant of your equation is  [ B² - 4 A C ] = 2² - 4(1)(-2) = 4 + 8 = 12

Your equation has two real, unequal roots.



4 0
3 years ago
Read 2 more answers
What is the slope of the line of (1,0) and (-1,-3)
Alinara [238K]

Slope formula: m = \frac{(y2-y1)}{(x2-x1)} (Knowing that m represents the slope)

Substitute (1,0) for (x1,y1), and (-1,-3) for (x2,y2)

Slope of the line of (1,0) and (-1,-3) is:

m = \frac{(-3-0)}{(-1-1)} = \frac{-3}{-2} = \frac{3}{2}  

(Simplify)

Slope of the line of (1,0) and (-1,-3) is \frac{3}{2}

6 0
3 years ago
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