Suppose that J and K are points on the number line. If Jk=5 and J lies at -12 where could K be located?
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Answer:
Critical value f(1)=2.
Minimum at (1,2), function is decreasing for and increasing for
is point of inflection.
When 0<x<3, function is concave upwards and when x>3, , function is concave downwards.
Step-by-step explanation:
1. Find the domain of the function f(x):
2. Find the derivative f'(x):
This derivative is equal to 0 at x=1 and is not defined at x=0. Since x=0 is not a point from the domain, the crititcal point is only x=1. The critical value is
2. For the derivative f'(x)<0, then the function is decreasing. For
the derivative f'(x)>0, then the function is increasing. This means that point x=1 is point of minimum.
3. Find f''(x):
When f''(x)=0, x=3 and
When 0<x<3, f''(x)>0 - function is concave upwards and when x>3, f''(x)>0 - function is concave downwards.
Point is point of inflection.
