All categories

2 years ago

An English muffin and two fried eggs contain 330 calories. Three English muffins and

Mathematics

1 answer:

nalin [4]2 years ago

3 0

Answer:

m+2e=330

3m+1e=515

use simultaneous formula to get

m=37

e=146.5

You might be interested in

A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 41 specimens and counts the number of

e-lub [12.9K]

Answer:

(53.3; 56.1)

Step-by-step explanation:

Given that:

Sample size, n = 41

Mean, xbar = 54.7

Standard deviation, s = 5.3

Confidence level, Zcritical at 90% = 1.645

Confidence interval :

Xbar ± Margin of error

Margin of Error = Zcritical * s/sqrt(n)

Margin of Error = 1.645 * 5.3/sqrt(41)

Margin of Error = 1.362

Lower boundary = 54.7 - 1.362 = 53.338

Upper boundary = 54.7 + 1.362 = 56.062

(53.3 ; 56.1)

6 0

3 years ago

What is the domain of the function f(x) =x+1/<br> X^2-6x+8?

SpyIntel [72]

Answer:

The domain of the function is all real values of x, except $x = 4$ and $x = 2$

Step-by-step explanation:

We are given the following function:

$f(x) = \frac{x+1}{x^2-6x+8}$

It's a fraction, so the domain is all the real values except those in which the denominator is 0.

Denominator:

Quadratic equation with $a = 1, b = -6, c = 8$

Using bhaskara, the denominator is 0 for these following values of x:

$\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4$

$x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4$

$x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2$

The domain of the function is all real values of x, except $x = 4$ and $x = 2$

8 0

3 years ago

For the function, f(x)=(9x+7)/(2x+4)

AVprozaik [17]

A. $f(x)=\frac{9x+7}{2x+4}\\f'(x)=\frac{(9)(2x+4)-(9x+7)(2)}{(2x+4)^2}\\f'(x)=\frac{(18x+36)-(18x+14)}{(2x+4)(2x+4)}\\f'(x)=\frac{22}{4x^2+16x+16}\\f'(x)=\frac{11}{2x^2+8x+8}\\\frac{11}{(2x+4)(x+2)}=0\\\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty$ - There are no critical points because the graph is neither continuous nor smooth. There is a discontinuity at x = 2.

B. $\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty$ - The absolute maximum is f(lim⇒-2_-) = infinity. The absolute minimum is f(lim⇒-2_+) = -infinity. This applies to the interval [-10, 7].

C. $f(x)=\frac{9x+7}{2x+4}\\f(0)=\frac{9(0)+7}{2(0)+4}\\f(0)=\frac{7}{4}\\f(0)=1.75\\f(5)=\frac{9(5)+7}{2(5)+4}\\f(5)=\frac{45+7}{10+4}\\f(5)=\frac{52}{14}\\f(5)=\frac{26}{7}\\f(5)=3.714$ - The absolute maximum is f(5) = 26/7 or 3.714. The absolute mimimum is f(0) = 1.75. This applies to the interval [0, 5]. Proof: graph f(x) at [0, 5] on a graph or graphing calculator.