Ok so first you need to put w and x in the equation —-> 13-0.5(10)+6(1/2) and now you just solve -0.5 times 10 is -5 so 13-(-5)+6(1/2) now multiply 6 times 1/2 which is 3 so now we have 13-(-5)+3= 21
Answer:
Continuous random variables: c and e
Discrete random variables: a, b, d
Step-by-step explanation:
We have to identify whether the random variable is discrete or continuous.
- A discrete variable is a variable whose value is obtained by counting.
- A continuous random variable X takes all values in a given interval of numbers.
- Thus, a continuous variable can have values in decimals but a discrete random variable cannot take values in decimals.
a. The number of statistics students now reading a book.
Discrete random variable since number of students cannot take decimal values.
b. The number of textbook authors now sitting at a computer.
Discrete random variable since number of textbooks cannot be expressed in decimals but counted.
c. The exact time it takes to evaluate 27 plus 72.
It is a continuous random variable as it may take all values within an interval of time.
d. The number of free dash throw attempts before the first shot is made.
It is a discrete random variable since the number of throws can always be whole number.
e. The time it takes to fly from City Upper A to City Upper B.
Time is a continuous random variable.
I’ll do it, math or reading?
corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color c)the marbles are different in color
Answer:
Step-by-step explanation:
<u><em>The probability was done with replacement.</em></u>
Probaility of an event happening
number of blue marbles= 2
number of green marbles=5
total number of marbles=7
(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)


(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)



(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)


