A) Composite function that represents how many flowers Iris can expect to bloom over a certain number of weeks is f[s(w)] = 50w + 25.
B) The unit of measurement for the composite function is flowers.
C) Number of the flowers for 30 weeks will be 1525.
<h3>What is a composite function?</h3>
A function is said to be a composite function when a function is written in another function. The composite function that represents the number of flowers is f[s(w)] = 50w + 25. and the number of flowers for 30 weeks is 1525.
Part A: Write a composite function that represents how many flowers Iris can expect to bloom over a certain number of weeks.
From the given data we will find the function for the number of flowers with time.
f(s) = 2s + 25
We have s(w) = 25w
f[(s(w)]=2s(w) + 25
f[(s(w)] = 2 x ( 25w ) +25
f[s(w)] = 50w + 25.
Part B: What are the units of measurement for the composite function in Part A
The expression f[s(w)] = 50w + 25 will give the number of the flowers blooming over a number of the weeks so the unit of measurement will be flowers.
Part C: Evaluate the composite function in Part A for 30 weeks.
The expression f[s(w)] = 50w + 25 will be used to find the number of flowers blooming in 30 weeks put the value w = 30 to get the number of the flowers.
f[s(w)] = 50w + 25.
f[s(w)] = (50 x 30) + 25.
f[s(w)] = 1525 flowers.
Therefore the composite function is f[s(w)] = 50w + 25. unit will be flowers and the number of flowers in 30 weeks will be 1525.
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Answer:
volume=12m
Step-by-step explanation:
width*length*height=volume
4m=width
3m=height
4m*3m=12m
12m=volume
Answer:
Step-by-step explanation:
27x - 45 - 4x + 9
23x - 36
The value of
,
, and
for each schools is given in the first picture below.
is the lower quartile
is the median
is the upper quartile
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
Two fraction between 0 and 1/2 and 1/3 and 1/6. 1/3 = .33 and 1/6= .16. we know that 1/3 is greater than 1/6 because the value is larger. .33 > .16
.33 is definitely greater than 1.6