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Oksanka [162]
3 years ago
9

The area of a rectangular patio is 5 5/8 square yards, and it's length is 1 1/2 yards. What is the patio's width in yards?

Mathematics
1 answer:
MAXImum [283]3 years ago
8 0
Hello there! Thank you for asking your question here at Brainly. I will be assisting you today with answering this problem, and will be teaching you how to deal with it on your own in the future.

First, let's take a look at our question, and evaluate it.

"The area of a rectangular patio is 5 5/8 square yards, and it's length is 1 1/2 yards. What is the patio's width in yards?"

To clarify this problem, we are looking for the patio's width.

Let's first understand what the area of a rectangular shape is.
The formula for the area of a rectangle is "Length times Width", or "L • W".

So this is how the equation should look like:
A = L • W
We have our area, 5 5/8, and we have our length, 1 1/2.

To make things more simple, let's convert our fractions to decimals. Now, to convert our fractions to decimals, let's set our denominators (the numbers on the bottom of a fraction) equal to another fraction, with x as the numerator (the numbers on the top of a fraction) and 100 as the denominator.

So we have 1/2 and x/100. Divide 100 by 2 to find x (as 1/2 of anything is dividing by 2).
100 / 2 = 50, so 1 1/2 = 1.50 as a decimal.

Now, let's try 5/8.
1/8 = 0.125, so multiply 0.125 by 5.
0.125 • 5 = 0.625.
5 5/8 = 5.625 as a decimal.

So, now we have our equation:
A = L • W
Plug in our numbers.
5.625 = 1.50x

To isolate and solve for x, we need to divide both sides by 1.50, so let's do that.
5.625 / 1.50 = 3.75
1.50x / 1.50 = x

We are now left with:
x = 3.75

Your answer is:
The patio's width is 3.75 yards.

I hope this helps!
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corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color  c)the marbles are different in color

Answer:

Step-by-step explanation:

<u><em>The probability was done with replacement.</em></u>

Probaility of an event happening=\frac{number of required outcomes}{number of possible outcomes}

number of blue marbles= 2

number of green marbles=5

total number of marbles=7

(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)

                                  =\frac{2}{7}*\frac{2}{7}

                                   =\frac{4}{49}

(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)

   =\frac{4}{49} + \frac{5}{7}*\frac{5}{7}

   =\frac{4}{49} + \frac{25}{49}

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(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)

  =\frac{2}{7}*\frac{5}{7}+ \frac{5}{7}*\frac{2}{7}

           =\frac{10}{49}+\frac{10}{49}

      =\frac{20}{49}

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