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Liono4ka [1.6K]
3 years ago
6

The answer=ajshabeel

Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

Answer:

It be like that sometimes...

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Which equation represents a line that passes through (–9, –3) and has a slope of –6?
Dahasolnce [82]
<h2>Hello!</h2>

The answer is:

The last equation,

y+3=-6(x+9)

<h2>Why?</h2>

To find which of the given equations represents a line that passes through the point (-9,-3) and has a slope of -6, we need to find an equation that can be satisfied by evaluating the given point.

We can see that the only equation that can be satisfied evaluating the point (-9,-3) is the last equation:

y+3=-6(x+9)

Evaluating the point, we have:

-3+3=-6*(-9+9)

0=-6*(0)

0=0

We can see that the equation is satisfied!

Also, we can see that evaluating the point into the other equations, they will not be satisfied.

Let's prove that:

Evaluating:

First equation:

y-9=-6(x-3)\\-3-9=-6*(-9-3)\\-12=-6*(-12)=72

The equation is not satisfied.

Second equation:

y+9=-6(x+3)\\-3+9=-6*(-9+3)\\6=-6*(-6)=36

The equation is not satisfied.

Third equation:

y-3=-6(x-9)

-3-3=-6(-9-9)

-6=-6(-18)=108

The equation is not satisfied.

Hence, the correct option is the last option, the equation that represents a line that passes through (–9, –3) and has a slope of –6 is the last equation:

y+3=-6(x+9)

Have a nice day!

Note: I have attached a picture for better understanding.

5 0
3 years ago
Read 2 more answers
please help :( I know that <img src="https://tex.z-dn.net/?f=2%5E%5Cfrac%7B6%7D%7B5%7D" id="TexFormula1" title="2^\frac{6}{5}" a
saul85 [17]

Answer:

\displaystyle 2^{\frac{6}{5}}=2\sqrt[5]{2}

Step-by-step explanation:

<u>Fractional Exponents</u>

An expression like

\displaystyle a^{\frac{n}{m}}

can be expressed as a radical of the form:

\sqrt[m]{a^n}

We have the expression:

\displaystyle 2^{\frac{6}{5}}

Its equivalent radical form is:

\displaystyle 2^{\frac{6}{5}}=\sqrt[5]{2^6}

Since the exponent is greater than the index of the radical, we can take 2 out of it by following the procedure:

\sqrt[5]{2^6}=\sqrt[5]{2^5\cdot 2}

Taking out 2^5 from the radical:

\sqrt[5]{2^6}=2\sqrt[5]{2}

Thus:

\displaystyle 2^{\frac{6}{5}}=2\sqrt[5]{2}

4 0
3 years ago
If abc+1=0, prove that: (1/1−a−b^-1)+(1/1−b−c^-1)+(1/1−c−a^−1​)=1​
shusha [124]

Answer:

Hope it will help. I did it.

Hope the image is clear.

6 0
3 years ago
Find the quadratic equation 3 and-5​
natulia [17]

Answer:

x^2 + 2x - 15 = 0.

Step-by-step explanation:

If you mean the equation with zeroes of 3 and -5 it is:

(x - 3)(x + 5) = 0

x^2 + 2x - 15 = 0.

7 0
3 years ago
A square pyramid of base 3cm by 3cm is made from 18cm3 of clay.
ss7ja [257]

Answer:

6 cms.

Step-by-step explanation:

Volume of the pyramid = 1/3 * area of base * height

= 1/3 * 3*3 * h = 18

1/3 * 9 * h = 18

3h = 18

h = 6 cm

7 0
3 years ago
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