The answer would be 30. Easy way is just to count 5,10,15,20,25,”30”.
If the first question mark is 3 then the next is 13 than the next still 13 and the right one 26 and then lastly x is equally to 2
Or
3x+9+10x=33
13x+9=33
13x=26
X=2
Tan3A=tan(2A+A)
We know that , tan(x+y)=(tanx + tany)/(1 - (tanx)(tany))
tan(2A+A)=(tan2A+tanA)/(1 - (tan2A)(tanA))— (1)
We know that , tan2x=2tanx/(1 - tan^2x)
So, by substituting tan2A in (1),we get,
=[2tanA/(1 - tan^2A) + tanA]/1- (2tanA/(1 - tan^2A))(tanA)]
=[2tanA+tanA - tan^3A]/[1 - tan^2A - 2tan^2A]
=[3tanA - tan^3A]/[1-3tan^2A]
Therefore, tan3A= [3tanA - tan^3A]/[1-3tan^2A]
Hello,
Shall we begin?
<span>= - 1 - (-5) . (-3) + ( - 4 ) 3 : ( - 4 )
</span>= -1 - 15 + ( -12 ) : (-4)
= -1 - 15 + 3
= - 16 + 3
= - 13
Answers: - 13
Omg why do we have to have 20 letters
true is the answer