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3 years ago

The graph shows the number of tacos ordered and the cost. What is the unit rate?

Mathematics

1 answer:

Pie3 years ago

3 0

(2,1), (4,2), (6,3) or (8,4) are the numbers we will use to find the first differences which will give us the unit rate

2/1 = 2
4/2= 2
6/3= 2
8/4= 2

therefore this graph is linear and its unit rate is 2.

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1. How many solitions does this equation have -4(5-3x)=12x+20

Rom4ik [11]

Answer:

1. no solutions

2. one solution

Step-by-step explanation:

1. -4(5-3x)=12x+20

-20+12x=12x+20

-40+12x=12x

-40=0?????

So no solutions.

2. 3x+7(x+1)=2(6x+5)+2

3x+7x+7=12x+10+2

10x+7=12x+12

-2x+7=12

-2x=5

x=-5/2

So one solution.

6 0

2 years ago

Read 2 more answers

What’s 1+1? Is it 929? Uwu

Allisa [31]

Answer:

No it's 2 Lol not 929 UwU

3 0

2 years ago

Solve the proportional equation 3/r = 5/r+3

romanna [79]

Answer:

r=9/2 or 4.5

Step-by-step explanation:

First of all our goal is to get R by itself

by cross multiplying we get,

(r+3)*3=5r

by distributive property we get

3r+9=5r

substracting 3r from both sides we get

9=2r

by dividing by 2 in both sides we get

r=9/2 or 4.5

6 0

2 years ago

When a = 6 and b = 22, C = 33. If c varies directly with b and inversely with a, which equation models the situation?

S_A_V [24]

Step-by-step explanation:

C=b/a

c=kb/a

where as k is the constant

c=kb/a

we substitute

33=22k/6

crossed multiply

33*6= 22k

198=22k

we divide both sides by 22

198/22=22k/22

K=9

4 0

2 years ago

A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 102

cupoosta [38]

Answer:

The upper endpoint of the 99% confidence interval for population proportion is 0.13.

Step-by-step explanation:

The confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

<u>Given:</u>

<em>n</em> = 1000

$\hat p$ = 0.102

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58$

*Use the standard normal table for the critical value.

Compute the 99% confidence interval for population proportion as follows:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)$

Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.

6 0

2 years ago