the answer to this question would be c- 15.6
I would assume it would be dividing both sides by three although if someone were to actually solve this I would say multiply 2 and 3 together first.
Hope this helps :)
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
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The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Answer:
9/1000
Step-by-step explanation:
convert the decimal numbers to a fraction by placing the decimal numbers over a power of ten. since there are 3 numbers to the right of the decimal point,place thw decimal numvers over 10^3 (1000).
