There are 6 bananas in a bunch and 4 monkeys want to share them

Mathematics

1 answer:

elixir [45]2 years ago

3 0

Answer:

1.5 banana each

Step-by-step explanation:

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Line A: (2, 6) and (-9, 3)

lesantik [10]

Answer:

use an online graph to graph it and look at any points lines intersect

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2 years ago

If C(x) = 4x^2 - 3, find the following<br> (a) C(0)<br> (b) C (-1)<br> (c) C (-2)<br> (d) C (-3/2)

NeTakaya

Step-by-step explanation:

$C(x)=4x^2-3\\\\C(0),\ C(-1),\ C(-2),\ C\left(-\dfrac{3}{2}\right)\\\\\text{Substitute each value}\ \left\{0, -1, -2, -\frac{3}{2}\right\}\ \text{instead}\ C(x):\\\\C(0)=4(0^2)-3=4(0)-3=0-3=-3\\\\C(-1)=4(-1)^2-3=4(1)-3=4-3=1\\\\C(-2)=4(-2)^2-3=4(4)-3=16-3=13\\\\C\left(-\dfrac{3}{2}\right)=4\left(-\dfrac{3}{2}\right)^2-3=4\left(\dfrac{9}{4}\right)-3=9-3=6$

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3 years ago

Linda needs 20 gallons of juice that has 75%fruit juice. she has a mixture that has 80% fruit juice and another mixtures that ha

suter [353]

Linda should use ...
15 gallons of 80% juice
5 gallons of 60% juice

_____
Let g represent the number of gallons of 80% juice needed. Then (20-g) is the number of gallons of 60% juice Linda will use. The amount of juice in the mixture can be written as
0.80g +0.60(20 -g) = 0.75×20
0.20g = 20(0.75 -0.60) = 20×0.15
g = 20×0.15/0.20 = 15
The amount of 80% juice needed is 15 gallons, so 5 gallons of 60% juice are needed.

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2 years ago

What if angle 6=50 then find angle 11 what would it be how would you do it

Mars2501 [29]

Is there a graph for this problem?

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2 years ago

For a binomial process, the probability of success is 40 percent and the number of trials is 5. Find the standard deviation.

Yakvenalex [24]

Answer:

$Sd(X) =\sqrt{1.2}=1.095$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=5, p=0.4)$