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Margarita [4]
3 years ago
11

There are 6 bananas in a bunch and 4 monkeys want to share them

Mathematics
1 answer:
elixir [45]3 years ago
3 0

Answer:

1.5 banana each

Step-by-step explanation:

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If ab = 20 cm and bc = 4 cm, then what are the possible lengths for ac so that ab, bc and ac can form a triangle?
telo118 [61]
16<ac<24
If it is less than 16 it will not form a triangle and if it is more than 24 the other two legs will not be larger than ac is.
3 0
3 years ago
Find the value of x.<br> 105°/15x
Natalija [7]

\text{The two angles are supplementary, so their measures add up to 180 degrees.}

~~~~~~15x+105 = 180\\\\\implies 15x = 180 -105\\\\\implies 15x = 75\\\\\implies x =\dfrac{75}{15}\\\\\implies x = 5

8 0
2 years ago
Need help ASAP <br> questions in the pics i have sent
Cloud [144]

Answer:

Step-by-step explanation:

Picture 1

In right triangle ABC,

Side AB is the opposite side of angle C.

Picture 2

In triangle MKL,

tan(∠M) = \frac{\text{Opposite side}}{\text{Adjacent side}}

             = \frac{KL}{KM}

             = \frac{15}{8}

Option (1) is the answer.

Picture 3

In ΔXYZ,

sin(∠Z) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

            = \frac{XY}{XZ}

For the length of XY we will apply Pythagoras theorem in ΔXYZ,

XZ² = XY² + YZ²

XY² = XZ² - YZ²

      = (40)² - (32)²

XY = √576

     = 24

sin(Z) = \frac{24}{40}

sin(Z) = \frac{3}{5}

Picture 4

In right triangle DEF,

Cos(D) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

           = \frac{EF}{DF}

           = \frac{75}{72}

           = \frac{25}{24}

Picture 5

In ΔABC,

tan(63°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(63°) = \frac{BC}{AB}

AB = \frac{BC}{\text{tan}(63)}

AB = \frac{8}{\text{tan}(63)}

AB = 4.0762 ≈ 4 m

Option (3) will be the answer.

7 0
3 years ago
A card is selected at random from a standard deck of playing cards.
notsponge [240]

|\Omega|=52\\|A|=4\\\\P(A)=\dfrac{4}{52}=\dfrac{1}{13}

7 0
3 years ago
If p(a) = 0.50, p(b) = 0.60, and p(a intersection
bogdanovich [222]
Use the identity P(A &cup; B) = P(A)+P(B)-P(A &cap; B)

P(A)=0.50
P(B)=0.60
P(A &cup; B) = 0.30
=>
P(A &cup; B) = P(A)+P(B)-P(A &cap; B)
=(0.50+0.60)-0.30
=0.80
5 0
3 years ago
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