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photoshop1234 [79]
3 years ago
11

You buy a car for $8000 that depreciates at a rate of 11% a year. How much is the

Mathematics
2 answers:
Fiesta28 [93]3 years ago
8 0

Answer: $4,467.2

Step-by-step explanation:

The formula for this is A = P (1 - r) ^t

Where p is the Principal, r is the rate and t= time

Given from the question, p = $8000

rate= 11% = 11/100 = 0.11

Time = 5 years

Slot the values into the formula:

A= 8000 (1 - 0.11) ^5

= 8000 (0.89)^5

8000 × 0.5584

=$4,467.2

After 5 years, the worth of the car would have depreciated to $4,467.2

I hope this helps.

MrRissso [65]3 years ago
6 0

Answer: $3600

Step-by-step explanation:

Principal (P) = $8000

Rate (R) = 11%

Time (T) = 5years

Let depreciation be X

X = P x R x T / 100

X = 8000 x 11 x 5 / 100

X = $4400

Therefore, Depreciation after 5years is given as ; P - X

= $8000 - $4400

= $3600

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Step-by-step explanation:

The speed, distance time formula is:

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Given:

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If Speed was 60 miles/hour the time taken is (t-\frac{1}{4}) hours.

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s=\frac{d}{t} \\60=\frac{d}{(t-\frac{1}{4}) }\\d=60t-15...(ii)

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d=30t\\=30\times\frac{1}{2} \\=15\ miles

Thus, the distance between Harry’s home and his office? is 15 miles.

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