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timama [110]
3 years ago
12

Which of the following is rational

Mathematics
1 answer:
Makovka662 [10]3 years ago
3 0
D is rational cause it continues
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Danielle bought a house for $215,000. She financed $189,375 of the purchase price with a 15-year-fixed-rate mortgage with a 6.1%
Brilliant_brown [7]
Total cost of the house = $215,000
Amount financed through mortgage = $189,375
Amount paid through other means (such as cash) = 215,000-189,375 = $25,625
Rate = 6.1% = 0.061
Number of years = 15 years

Monthly payment, M = P[i(1+i/12)^12*15]/[(1+i/12)^12*15 -1] = 189,375[0.061/12(1+0.061/12)^12*15]/[(1+0.061/12)^12*15 - 1] = $1,608.30
Total amount paid = $25,625 + (M*12*15) = $25,625 + $289,494.56 = $315,119.56

Seems the options given don't match the correct answer.
4 0
3 years ago
A)x 1/9
STALIN [3.7K]

Answer:

Answer should be x^9

Step-by-step explanation:

This equation looks really complicted, but it's actually much easier when you break it down! First, your going to multiply the fraction 3/2 by 6 - since one is a fraction, youre going to find the GCF, or Greatest Common Factor, and reduce it. The GCF in this equation is 2, so we eliminate the two from the fraction (making it just 3) and divide 6 by 2 (getting 3). Thus, we are left with (x^3)^3 -> 3 x 3 = 9. So we are left with x^9. I hope this helps!

5 0
3 years ago
Write the equation of a line in slope-intercept form that passes through the given points.
ruslelena [56]

Answer:

<h2>         y = 0.25x + 2</h2>

Step-by-step explanation:

\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}

(0, 2)    ⇒     x₁ = 0,  y₁ = 2

(-4, 1)     ⇒     x₂ = -4,  y₂ = 1

So the slope:

\bold{m=\dfrac{1-2}{-4-0}=\dfrac{-1}{-4}=0.25}

The point-slope form of the equation of the line passing through point (x₀,y₀) and with slope m is:  y - y₀ = m(x - x₀)

m = 0.25

(0, 2)    ⇒     x₀ = 0,  y₀ = 2

Therefore:

               y - 2 = 0.25(x - 0)

               y - 2 = 0.25x                  {add 2 to both sides}

               y = 0.5x + 2          ←  the slope-intercept form of the equation

5 0
3 years ago
For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec
telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

4sin(x^2) = 0

sin(x^2) = 0

x^2 = n\pi where n = 0, 1, 2,3, 4, 5,...

x = \sqrt(n\pi)

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0

xcos(x^2) = 0

x = 0 or

cos(x^2) = 0

x^2 = \frac{\pi}{2} + n\pi where n = 0, 1, 2, 3

x = \sqrt{\pi(n+1/2)}

Since we are restricting x between 0 and 3 we can stop at n =  2

So our critical points are at

x = 1.25, y = f(1.25) = 4sin(1.25^2) = 4

x = 2.17 , y = f(2.17) = 4sin(2.17^2) = -4

x = 2.8, y = f(2.8) = 4sin(2.8^2) = 4

For the inflection point, we can take the 2nd derivative and set it to 0

f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0

cos(x^2) = 2x^2sin(x^2)

tan(x^2) = \frac{1}{2x^2}

We can solve this numerically to get the inflection points are at

x = 0.81, y = f(0.81) = 4sin(0.81^2) = 2.44

x = 1.81, y = f(1.81) = 4sin(1.81^2) = -0.54

x = 2.52, y = f(2.52) = 4sin(2.52^2) = 0.27

3 0
3 years ago
The side of a square is 2^7/2. Using the area formula A = s^2, determine the area of the square.
sergij07 [2.7K]
The answer is 49 square inches?

5 0
3 years ago
Read 2 more answers
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