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Yuri [45]
3 years ago
8

NEED HELP WITH A MATH QUESTION WITH FINDING A SURFACE AREA OF A SQAURE PYRAMID

Mathematics
1 answer:
GalinKa [24]3 years ago
3 0

ANSWER

S.A = 125 {in}^{2}

EXPLANATION

The total surface area of a square pyramid is the area of the 4 triangular faces plus the area of the square base.

This is given by the formula!

S.A = 4 \times  \frac{1}{2} bh +  {l}^{2}

From the diagram, the base is 5 inches and the height is 10 inches.

We substitute the values to get:

S.A = 4 \times  \frac{1}{2}  \times 5 \times 10 +  {5}^{2}

This simplifies to;

S.A = 100 +  25

S.A = 125 {in}^{2}

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A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
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Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

3 0
3 years ago
I need 3 questions answered please.​
kakasveta [241]

Answer:

3) \:  \: 113 {ft}^{2}

4) \: false

5) \: 70 {ft}^{2}

Step-by-step explanation:

3) Area of a circle is

\pi \times  {r}^{2}

Where r = 6

Thus,

area =   \frac{22}{7}  \times  {6}^{2}

area =  \frac{22}{7}  \times 36

area = 3.143 \times 36

area = 113 {ft}^{2} \: (nearest \: whole \: number)

4) False

Area of a circle is measured by the formula below:

area = \pi \times  {r}^{2}

5) The formula for calculating the area of a rectangle is given thus:

area \: of \: a \: rectangle = l \times w

Where, l = 10ft; w = 7ft

area = 10ft \times 7ft = 70 {ft}^{2}

8 0
3 years ago
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