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loris [4]
3 years ago
10

The stock market in 2008 has gone through drastic changes. On December 3rd, 2008 the Dow Jones Industrial Average (DJIA) closed

the day at 8,591.69 points. On December 4th of the same year, the DJIA decreased by 2.51% of its December 3rd closing. On December 5th of the same year, the DJIA increased by 3.09% of its December 4th closing. Determine what the DJIA closed at on December 5th. Round your answer to the nearest point.
a.
8,631.78 points
c.
8,634.86 points
b.
8,750.35 points
d.
9,079.49 points
Mathematics
1 answer:
tigry1 [53]3 years ago
3 0

Answer:

C, 8,634.86

Step-by-step explanation:

Starting with 8,591.69

2.51% of 8,591.69 is 215.651419

subtract that from 8,591.69 and you get 8376.038581

3.09% of 8376.038581 is 258.819592153

258.819592153+8376.038581=8634.85817315

8,634.86 is your final answer

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hey certain cars value is said to depreciate by approximately 15% each year for the first eight years of the car originally cost
soldi70 [24.7K]

Answer:0.0625

Step-by-step explanation:

7 0
4 years ago
What is (4+2) (-5) +3 (2+ -3 + 2
Mariulka [41]
<span><span><span>(<span>4+2</span>)</span><span>(<span>−5</span>)</span></span>+<span>3<span>(<span><span>2−3</span>+2</span>)
</span></span></span><span>=<span><span><span>(6)</span><span>(<span>−5</span>)</span></span>+<span>3<span>(<span><span>2−3</span>+2</span>)
</span></span></span></span><span>=<span><span>−30</span>+<span>3<span>(<span><span>2−3</span>+2</span>)
</span></span></span></span><span>=<span><span>−30</span>+<span>3<span>(<span><span>−1</span>+2</span>)
</span></span></span></span><span>=<span><span>−30</span>+<span><span>(3)</span><span>(1)
</span></span></span></span><span>=<span><span>−30</span>+3
</span></span><span>=<span>−<span>27</span></span></span><span>
Hope this helps</span>
5 0
3 years ago
Read 2 more answers
2
Anika [276]

Answer:

3 : 2

Step-by-step explanation:

27 : 18 reduce the numbers = 3 : 2

3 0
3 years ago
What is the measure of Zy?<br> 139 yº
andriy [413]

Answer:

y = 41°

Step-by-step explanation:

∡ y and 139° are adjacent angles and sum to 180° , that is

∠ 1 + 139° = 180° ( subtract 139° from both sides )

∠ 1 = 41°

3 0
3 years ago
Here we will study the function f (x) = e ^ x sin (x), where x ∈ [0, 2π]. a) Determine where the function is decreasing and incr
Semmy [17]

fff

f(x) = e^x sin (x)

To find increasing and decreasing intervals we take derivative

f'(x) = e^xsin(x)+e^x(cosx)= e^x(sinx+cosx)

Now we set the derivative =0  and solve for x

e^x(sinx+cosx)=0

sinx + cosx =0

divide whole equation by cos x

\frac{sinx}{cosx} + \frac{cosx}{cosx} =0

tanx +1 =0

tanx = 1

x=\frac{3\pi }{4} and  x=\frac{7\pi}{4}

Now we pick a number between 0 to  \frac{3\pi }{4}

Lets pick  \frac{\pi }{2}

Plug it into the derivative

f'(x) =e^{\frac{\pi }{2}}(sin(\frac{\pi}{2})+cos(\frac{\pi }{2}))

= 4.810 is positive

So the graph of f(x) is increasing on the interval [0, x=\frac{3\pi }{4})

Now we pick a number between   \frac{7\pi}{4} to 2pi

Lets pick  \frac{11\pi}{6}

Plug it into the derivative

f'(x) =e^{\frac{11\pi}{6}}(sin(\frac{11\pi}{6})+cos(\frac{11\pi }{6}))

= 116 is positive

So the graph of f(x) is increasing on the interval (\frac{7\pi }{4}, 2\pi)

Increasing interval is (0,\frac{3\pi }{4}) U (\frac{7\pi }{4}, 2\pi)

Decreasing interval is (\frac{3\pi}{4}, \frac{7\pi}{4})

(b)

The graph of f(x) increases and reaches a local maximum at x=\frac{3\pi}{4}

The graph of f(x) decreases and reaches a local minimum at x=\frac{7\pi}{4}

(c)

f(0) = 0

f(2\pi)=0

f(\frac{3\pi }{4})=7.46

f(\frac{7\pi}{4})=-172.64

Here global maximum at x=\frac{3\pi}{4}

Here global minimum at x=\frac{7\pi}{4}


3 0
4 years ago
Read 2 more answers
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