Answer:
Explanation:
The sheet name at the footer of the screen gets changed from sheet1 to inventory.
An optimization problem is one in which you want to find, not just a solution, but the best solution •<span>A <span>“greedy algorithm” sometimes works </span></span><span>well for optimization problems </span>•<span>But only a few optimization problems can </span><span> be solved by the <span>greedy method</span></span>
From the creator of the network
Answer:
- #include <iostream>
- using namespace std;
- int main()
- {
- const int NUM_VALS = 4;
- int hourlyTemp[NUM_VALS];
- int i;
-
- for (i = 0; i < NUM_VALS; ++i)
- {
- cin >> hourlyTemp[i];
-
- }
-
- /* Your solution goes here */
- for(i = 0; i < NUM_VALS; ++i){
-
- if(i < NUM_VALS -1){
- cout<<hourlyTemp[i]<<",";
- }
- else{
- cout<<hourlyTemp[i];
- }
- }
- cout << endl;
- return 0;
- }
Explanation:
The solution code is given from Line 18 - 26. To print the element from array one after another, we create a for loop to traverse through every element in the array (Line 18). Create an if condition to check if the current index i is not the last index, print the element followed with a comma (Line 20 -22). Otherwise print only the element (Line 23 - 25).
