Answer:
Let the two string type variables be var1 and var2. The value stored in these two variables is : The "use" of quotations causes difficulties.
- The variable which uses quoted string:
string var1 = "The \"use\" of quotations causes difficulties.";
- The variable which does not use quoted string:
string var2 = "The " + '\u0022' + "use" + '\u0022' + " of quotations causes difficulties.";
- Another way of assigning this value to the variable without using quoted string is to define a constant for the quotation marks:
const string quotation_mark = "\"";
string var2 = "The " + quotation_mark + "use" + quotation_mark + " of quotations causes difficulties.";
Explanation:
In order to print and view the output of the above statements WriteLine() method of the Console class can be used.
Console.WriteLine(var1);
Console.WriteLine(var2);
In the first statement escape sequence \" is used in order to print: The "use" of quotations causes difficulties. This escape sequence is used to insert two quotation marks in the string like that used in the beginning and end of the word use.
In the second statement '\u0022' is used as an alternative to the quoted string which is the Unicode character used for a quotation mark.
In the third statement a constant named quotation_mark is defined for quotation mark and is then used at each side of the use word to display it in double quotations in the output.
Answer: Linked cell
Explanation: I just did a test
Answer:
retupmoc
Explanation:
1.) Anwser will be retupmoc
because
public static String mysteryString(String s){
if(s.length() == 1){
return s;
}
else{
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
}
}
In this program input is "computer" . So the function mysteryString(String s) it does
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
so when it enters the first time ??s.substring(s.length() -1) and it will be give you 'r' then it calls the function recursively by reducing the string length by one . So next time it calls the mysteryString function with string "compute" and next time it calls return s.substring(s.length()-1)? + mysteryString(s.substring(0,s.length-1)) so this time it gives "e" and calls the function again recursively . It keeps on doing till it matched the base case.
so it returns "retupmoc".
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