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sukhopar [10]
3 years ago
6

I cant figure this out, can I get some help?

Computers and Technology
1 answer:
Natalija [7]3 years ago
3 0

Answer:

i think it is 25 0 33.

Explanation:

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Which term refers to a solution to a large problem that is based on the solutions of smaller subproblems. A. procedural abstract
valentina_108 [34]

Answer:

procedural abstraction

Explanation:

5 0
3 years ago
Write a program that calculates and displays the amount ofmoney available in a bank account that initially has $8000 deposited i
Leviafan [203]

Answer:

Written in Python

import math

principal = 8000

rate = 0.025

for i in range(1, 11):

    amount = principal + principal * rate

    principal = amount

    print("Year "+str(i)+": "+str(round(amount,2)))

Explanation:

This line imports math library

import math

This line initializes principal amount to 8000

principal = 8000

This line initializes rate to 0.025

rate = 0.025

The following is an iteration from year 1 to 10

for i in range(1, 11):

    This calculates the amount at the end of the year

    amount = principal + principal * rate

    This calculates the amount at the beginning of the next year

    principal = amount

    This prints the calculated amount

    print("Year "+str(i)+": "+str(round(amount,2)))

6 0
3 years ago
given an array of integers a, your task is to count the number of pairs i and j (where 0 ≤ i < j < a.length), such that a[
Nimfa-mama [501]

Using the knowledge of computational language in C++ it is possible to write a code that given an array of integers a, your task is to count the number of pairs i and j.

<h3>Writting the code:</h3>

<em>// C++ program for the above approach</em>

<em> </em>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em> </em>

<em>// Function to find the count required pairs</em>

<em>void getPairs(int arr[], int N, int K)</em>

<em>{</em>

<em>    // Stores count of pairs</em>

<em>    int count = 0;</em>

<em> </em>

<em>    // Traverse the array</em>

<em>    for (int i = 0; i < N; i++) {</em>

<em> </em>

<em>        for (int j = i + 1; j < N; j++) {</em>

<em> </em>

<em>            // Check if the condition</em>

<em>            // is satisfied or not</em>

<em>            if (arr[i] > K * arr[j])</em>

<em>                count++;</em>

<em>        }</em>

<em>    }</em>

<em>    cout << count;</em>

<em>}</em>

<em> </em>

<em>// Driver Code</em>

<em>int main()</em>

<em>{</em>

<em>    int arr[] = { 5, 6, 2, 5 };</em>

<em>    int N = sizeof(arr) / sizeof(arr[0]);</em>

<em>    int K = 2;</em>

<em> </em>

<em>    // Function Call</em>

<em>    getPairs(arr, N, K);</em>

<em> </em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/17544466

#SPJ4

4 0
1 year ago
Which of the following statements about the use of desktop publishing software is true? A. There's no visible difference between
xxTIMURxx [149]
The correct answer to the question is option D.

A good number of desktop publishers would rather create the text portion of their documents using a word processing program, and then import the text into a desktop publishing file. Thankfully, w<span>ord processing programs are compatible with desktop publishing and other software programs.</span>
8 0
2 years ago
Suppose a program takes 1000 machine instructions to run from start to end, and can do that in 10 microseconds when no page faul
Tema [17]

Answer:

(10^6 + 9.9)

Explanation:

Given:

Total number of machine instructions = 1000

Number of page fault in 100 instructions = 1

Number of page faults in 1000 instructions = 10

Time to serve one page fault = 100 milliseconds

Time to serve ten page faults = 100*10 milliseconds = 1000 milliseconds = 10^6 Microseconds

Number of instructions without any page fault = 1000 - 10 = 990

Time required to run 1000 instructions = 10 Microseconds

So, time required to run 990 instructions = (10*(990/1000)) Microseconds = 9.9 Microseconds

So, the total time required to run the program = (10^6 + 9.9) Microseconds

3 0
3 years ago
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