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Lynna [10]
3 years ago
11

Comment on the following 2 arrays. int *a1[8]; int *(a2[8]); a1 is pointer to an array; a2 is array of pointers a1 is pointer to

an array; a2 is pointer to an array a1 is array of pointers; a2 is pointer to an array a1 is array of pointers; a2 is array of pointers
Computers and Technology
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

The answer is "a1 and a2 is an array of pointers".

Explanation:

In this question, A collection of pointers refers to an array of elements where each pointer array element points to a data array element. In the above-given statement, the two-pointer type array "a1 and a2" is declared that holds the same size "8" elements in the array, and each element points towards the array's first element of the array, therefore, both a1 and a2 are pointer arrays.

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Harlamova29_29 [7]

Answer:

arrange the steps below to outline what maia needs to do to accomplish this task.

Explanation: :´(

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3 years ago
One lap around a standard high-school running track is exactly 0.25 miles. Write the function miles_to_laps() that takes a numbe
lana [24]

Answer:

def miles_to_laps(user_miles):

   laps = user_miles / 0.25

   

   return laps

 

miles = float(input("Enter number of miles: "))

print('{:.2f}'.format(miles_to_laps(miles)))

Explanation:

Create a function named miles_to_laps that takes one parameter, user_miles

Inside the function, calculate the number of laps, divide the user_miles by 0.25 (Since it is stated that one lap is 0.25 miles). Return the laps

Ask the user to enter the number of miles

Call the function with that input and print the result in required format

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3 years ago
Which type of disk uses primary partitions, extended partitions, and logical drives to organize data?
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8 0
2 years ago
What is communication ????<br>​
Delicious77 [7]

Answer:

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8 0
1 year ago
Read 2 more answers
Recall the binary search algorithm.1. Using the algorithm/algorithmic environment, give pseudocode using a for loop.AnswerMy alg
faust18 [17]

Answer:

Following are the Pseudo Code to the given question:

Explanation:

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Defines the A function (node, element)

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Loop Break

That element if node. value becomes lower than that

Node is node equivalent.

right

Using other nodes is node equivalent.

 left

Node Return

If the node is vacant

print the Tree is empty

Following are the pseudo-code by using the while loop:

Defines the function A(node,element)

While this node is not zero.

if the value of the node equals the element

Loop Break

The element if node. value is lower than

Node is node equivalent.

right

Using other nodes is equivalent to an a.left node

Node Return

If the node is vacant

print Tree is empty

following are the Pseudo-code for recursion:

Set the function A (node, key)

If no root is the same as the root or no root.

return the root.

If the root value is lower than that of the quest for key return (root. right, key)

Return your lookup (root.left,key)

 

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2 years ago
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