58 books can be expected to be turned in overdue
Yes, HL would be correct.
This states that if two hypotenuses are congruent (they have the same one)
and if one pair of legs are congruent,
the figure is congruent.
I hope this helps!
~cupcake
Answer:
Step-by-step explanation:
2(L+B)
Where L is the length and B is the breadth.
The theorem does not apply.
1. Set the function f(x)=sqrt(x-1) equal to 0 to find what values of x make f(x) defined. So:
x - 1 is < or = to 0
x > or = to 0
2.) find the values where x is defined:
x - 1 > or = to 0
x > or = to 0
Domain = all values of x that define f(x)
[1,infinity)
{x|x> or = to 1}
DNE because 1 is not in the domain because (1-1)^1/2 = 0.
