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Paraphin [41]
1 year ago
8

For every $2 that Miguel saves his parents give him $4 if Miguel saves $60 how much money will his parents give him

Mathematics
1 answer:
Nastasia [14]1 year ago
6 0
60/2 equals 30 then 30x4 is 120. Is parents give him a 120$
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Answer: 51

Step-by-step explanation:

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Which piecewise function below represents the function f(x)=x?(Only have 2 hours to answer)
irinina [24]

Answer:

f(z)={3z-30. if 0<z<10}

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3 years ago
Jackson has 2,000 baseball cards in his collection. Gabe has 1/10
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2,000 x 1/10 = 200. If it's not an answer tell me.
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3 years ago
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The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base and PA = 2sqrt5 in. The base edges AB = 10 in, AC
DIA [1.3K]

Answer:

PQ = √84 = 2√21 in ≈ 9.165 in

Step-by-step explanation:

The base edges AB = 10 in, AC = 17 in, and BC = 21 in

Q ∈ BC and AQ is the altitude of the base.

Let BQ = x in ⇒ CQ = (21 - x) in

ΔAQB a right triangle at Q

∴ AQ² = AB² - BQ² = 10² - x²  ⇒(1)

ΔAQC a right triangle at Q

∴ AQ² = AC² - CQ² = 17² - (21-x)²  ⇒(2)

Equating (1) and (2)

∴  10² - x² = 17² - (21-x)²

∴ 10² - x² = 17² - (21² - 42x + x²)

∴  10² - x² = 17² - 21² + 42x - x²

∴ 10² - 17² + 21² = 42x

∴ 42x = 252

∴ x = 252/42 = 6

Substitute at (1)

∴ AQ² = AB² - BQ² = 10² - x² = 100 - 36 = 64 = 8²

∴ AQ = 8 in

∵ The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base

∴ PA⊥AQ

∴ ΔPAQ is a right triangle at A,

PA = 2sqrt5 in  and AQ = 8 in

∴ PQ (hypotenuse) = √(PA² + AQ²)

∴ PQ = √[(2√5)² + 8²] = √(20+64) = √84 = 2√21 in ≈ 9.165 in

6 0
2 years ago
the position of a submarine relative to the water surface was -32 1/4 feet . A downward navigational manuever increased it's dep
tester [92]

Answer:

Position of the submarine now relative to the water surface =-47\ \frac{3}{4}

Step-by-step explanation:

It says that the position of a submarine relative to the water surface was -32 1/4 feet . A downward navigational maneuver increased it's depth by 15 1/2 feet.

Now we need to find about what is the position of the submarine now relative to the water surface.

Downward navigation means we 15 1/2 is negative

so we will just add both values to get the final answer:

Position of the submarine now relative to the water surface = -32\ \frac{1}{4}-15\ \frac{1}{2}

=-32\ \frac{1}{4}-15\ \frac{2}{4}

=-47\ \frac{3}{4}


5 0
3 years ago
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