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3 years ago

Does -2 (6 - 3x) = -12 + 6x have any solutions?

Mathematics

2 answers:

Natalija [7]3 years ago

8 0

Answer:

No solution

Step-by-step explanation:

-2 (6 - 3x) = -12 + 6x

-12+6x=-12+6x

Similar term cancel from both side so they have no solution

Sedbober [7]3 years ago

7 0

First to answer

Answer:

This equation has Infinite solutions! or should i say that All real numbers are solutions.

Let me know if it is correct!

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coffee worth 90 cents per pound is mixed with coffee worth 60 cents per pound ro produce a twenty pound blend worth 72 cents per

Evgesh-ka [11]

90x+60y=72
60y=-90x+72
y=-1.5x+1.2

then create a graph using this formula.

Hope this helps!

8 0

3 years ago

As of April 2006, roughly 50 million web domain names were registered (e.g., ). How many domain names consisting of just two let

Furkat [3]

Answer:

a) 676, 1296

b) 17576, 46656

c) 456976, 1679616

Step-by-step explanation:

firstly we know that there are 26 letters in the alphabet.

there are 26 ways of choosing the first character and 26 ways choosing the second character,

Therefore, the possible number of domains with two leeter is;

n = 26²

= 26 × 26

= 676

now when the digits are allowed, there are 26 + 10 = 36 characters to be used in total

therefore the possible number of domains with two characters is;

n = 36²

= 36 × 36

= 1296

there are 26 ways of choosing each character

therefore, the possible number of domains with three letters is

n = 26³

= 26 × 26 × 26

= 17576

when the digits are allowed, there are 26 + 10 = 36 characters to be used in total

therefore , the possible number of domains with three characters is;

n = 36³

= 36 × 36 × 36

= 46656

there are 26 ways of choosing each character, therefore the possible number of domains with four letters is;

n = 26⁴

n = 26 × 26 × 26 × 26

n = 456976

when the digits are allowed, there are 26 + 10 = 36 characters to be used in total

therefore, the possible number of domains with four characters is;

n = 36⁴

n = 36 × 36 × 36 × 36

= 1679616

7 0

3 years ago

An arithmetic progression is a sequence of numbers in which the distance (or difference) between any two successive numbers if t

earnstyle [38]

Answer:

Step-by-step explanation:

Solution:

- We are to write a program for evaluating the sum to Nth of an arithmetic sequence such that the sequence starts from positive integer 1, 3 , 5 , 7 , .. n.

- The sum to nth for the arithmetic series is given by two parameters i.e first integer a = 1 and the distance between successive integers d = 2 in our case.

- For any general distance d we can write our sum to nth as:

Sum to nth = a + (a+d) + (a+2*d) + (a+3*d) .... (a + (n-1)*d)

- From above sequence we can see that every successive number is increased by distance d and added in previous answer.

- We will use an iteration loop for a variable "sum", which is cycled by a "range ( , , )" function.

- The parameters of the range functions corresponds to:

range ( first integer , last integer , step size )

range ( a , n + 1 , d )

- Then we can cast the loop as follows:

" int sum = 0

int d = 2

int a = 1

for i in range ( a , n + 1 , d )