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1 year ago

Given circle E with diameter CD and radius EA. AB is tangent to Eat A.

Mathematics

1 answer:

faust18 [17]1 year ago

8 0

The hypotenuse is equal to the square of the other two sides. The length of AC from the diagram is 21.9feet

<h3>Application of pythagoras theorem</h3>

The theorem states that the square of the hypotenuse is equal to the square of the other two sides

Given the following

Hypotenuse = 26 feet = CD
Base side = AD = 14ft

Required

Length AC

Use the theorem

26^2 = 14^2 + AC^2

AC^2 = 676 - 196
AC^2 = 480
AC = 21.9feet

Hence the length of AC from the diagram is 21.9feet

Learn more on pythagoras theorem here: brainly.com/question/343682

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The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.

djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

where,

$r_1$ = radius of sphere = $\frac{Diamtere}{2}=\frac{8cm}{2}=4cm$

$r_2$ = radius of cylindrical wire = $\frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm$

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

$\frac{4}{3}\times r_1^3=r_2^2h$

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$h=8533.33cm\approx 8533cm$

Therefore, the length of the wire is, 8533 cm

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3 years ago