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2 years ago

Solve using elimination. x-2y=10 3x+y=-12

Mathematics

1 answer:

Nat2105 [25]2 years ago

5 0

Answer:

x-2y=10-------equation 1

3x+y=-12-------equation 2

multiply equation 1 by 3 and subtract eqn 2 by equation 1 then we get,

3x-6y=30

3x+y=-12

(-) (-) (+)

---------------

-7y=42

or, -y= 42÷7

or, y=-6

put the value of y in equation 1

x-2×(-6)=10

or, x+12=10

or x=10-12

or, x = -2

therefore x = -2 and y=-6 ans.

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A rectangle has an area of 45x2 − 42x − 48 and a width of 5x − 8. what is the length of the rectangle? to find the length of the

kondaur [170]

If the area and width of the rectangle are 45x² − 42x − 48 and (5x − 8) then the length of the rectangle will be (3x + 2).

<h3>What is a rectangle?</h3>

It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a rectangle, opposite sides are parallel and equal and each angle is 90 degrees. And its diagonals are also equal and intersect at the mid-point.

A rectangle has an area of 45x² − 42x − 48 and a width of 5x − 8.

Then the length of the rectangle will be

area = length × width

Then we have

Area = 45x² − 42x − 48

Then the factor of the polynomial will be

Area = (5x − 8)(3x + 2)

Then the length of the rectangle will be (3x + 2).

More about the rectangle link is given below.

brainly.com/question/10046743

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