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Norma-Jean [14]
3 years ago
6

Ethan and Sam work at different department stores. Ethan is paid 125$ per week and an 8% commission on sales, while Sam is paid

200$ per week and a 6% commission on sales. Enter the amount in dollars of sales for which they earn the same weekly income
Mathematics
1 answer:
kkurt [141]3 years ago
3 0

Answer:

3750$

Step-by-step explanation:

Let x be the amount in dollars of sales:

125 + 0.08x = 200 + 0.06x (when Ethan and Sam earn the same weekly income)

0.02x = 75

x = 3750

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Julli [10]
Lol hiiiiiiiiiiiiiiiiii
7 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Original price: $33.75, markdown 75%
Cloud [144]

Answer:

$25.31

Step-by-step explanation:

If you multiply 33.75 by .75 you get your answer.

4 0
3 years ago
Read 2 more answers
If a tree 41.8 feet tall casts a shadow that is 27 feet long, find the height of a tree casting a shadow that is 18.3 feet long
Neko [114]

Answer:

28.3 feet

Step-by-step explanation:

Given a tree 41.8 feet tall casts a shadow that is 27 feet long

So the Tangent of the angle of the sahdow remains the same for the both trees.

We know that  Tanx=\frac{height of the tree}{length of the shadow}

\frac{height of the tree1}{length of the shadow1} = \frac{height of the tree2}{length of the shadow2}

\frac{41.8}{27} =\frac{x}{18.3}

x=\frac{41.8}{27}\times18.3 =28.3

Therefore the height of the tree is 28.3 feet

6 0
3 years ago
I have a hard time with fractions and I need help. <br><br> 6 2/3 × 5/6=
laila [671]

When you multiply fractions you want to make them a mixed number then multiply the two top numbers together and then the bottom two together. Basically 6 2/3 would become 20/3 x 5/6... then multiply 5 and 20 together and 3 and 6 together to get 100/18... simplify from there.

5 0
3 years ago
Read 2 more answers
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