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2 years ago

Help!! are x and y proportional?

Mathematics

2 answers:

Nataliya [291]2 years ago

8 0

Yes it is proportional and you can tell there are by looking at y

Luda [366]2 years ago

7 0

Yes because both x and y go up the same amount each time...for example, the x goes up by 1/3 each time and the y goes up by 8 each time

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5) Two machines M1, M2 are used to manufacture resistors with a design

Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that $\mu = 1050, \sigma = 100$

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1100 - 1050}{100}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915.

X = 900

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{900 - 1050}{100}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that $\mu = 1000, \sigma = 120$

X = 1100

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1100 - 1000}{120}$

$Z = 0.83$

$Z = 0.83$ has a pvalue of 0.7967.

X = 900

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{900 - 1000}{120}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0

2 years ago

Which expression is equivalent to b^m•b^n<br> A. b^m-n<br> B. b^m•n<br> C. b^m÷n<br> D. b^m+n

Step2247 [10]

$\displaystyle\\ 
\bold{b^m \times b^n = b^{m + n}~~~(D)}\\\\ 
\bold{\frac{b^m}{b^n}= b^{m - n}~~~~~~~~~(A)}\\\\ 
\bold{\Big(b^m \Big)^n = b^{m\times n}~~~~(B)}\\\\ 
\bold{\sqrt[\bold{n}]{\bold{b^m}} = b^{m\div n } ~~~~~~(C)}$

6 0

2 years ago

George is comparing two different phones. The screen of phone A has a width of 5.3 cm. The width of the screen on phone B

bija089 [108]

Answer:

To answer this question, you need to makes the unit of the smartphone screen same. In this case, phone A is using decimal and phone B is using a fraction. You can use which was easier.

Let's try to use decimal. Then you need to convert phone B fraction width into decimal width. The calculation would be: 5cm + 1/3cm= 5 cm + 0.333cm= 5.333cm

From here it clear that phone B has a wider screen than phone A.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

In 2014, adele sold 2,500,000 records. In 2015, she sold 90% of the number of records she sold in 2014. In 2016, she sold 80% of

Alla [95]

She sold 70% bc 100% - 90% - 80% -70%

8 0

1 year ago

Read 2 more answers

A small cargo plane currently has 140 pounds of cargo aboard. In addition, n boxes weighing 45 pounds each will be brought aboar

Vika [28.1K]

Answer:

The inequality that represents this situation is: $140 + 45*n < p$

Step-by-step explanation:

Since the plane already had 140 pounds on board and "n" boxes will be loaded on it, then the weigh of each box multiplied by the number of box should be the extra cargo on the plane. This extra cargo added to the previous load must be less than the limit of cargo the plane can take as shown below:

$140 + 45*n < p$

3 0

2 years ago