Answer:
17. C " TAAGCTG". It would be the replication strand because A always pairs with T and C always pairs with G, so replication strands just have the opposite base as the original strand
18. Transcription is the name given to the process in which DNA is copied to make a complementary strand of RNA. RNA then undergoes translation to make proteins. The major steps of transcription are initiation, promoter clearance, elongation, and termination.
19. Straight hair is controlled by a recessive allele because as you can see the one where is not shaded is the one that has the most. There are only 1 shaded circle or square, out of the 12 other circles or square that is not shaded. This means that it is the recessive allele because people are less prone to getting straight hair, as you can see in that diagram.
Wasn't this the same question you asked earlier?
Carnoives eat meat and herbivores eat plants
The answer is a. because bacteria are prokaryotes and therefore don't have mitochondria
Answer:A frozen dinner at a grocery store is purchased for $2.20 wholesale and is marked up by 40 percent. A customer wants to buy four frozen dinners. How much will the customer pay, including paying 9 percent sales tax? Round your answer to the nearest cent.
Explanation: that’s the nearest hundredth.
Answer:
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0
Explanation:
According to Levin's model (1969):
<em>dP/dt = c - e</em>
where P represents the proportion of occupied patches.
<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.
Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:
- if dP/dt >0, then P is increasing with time
- if dP/dt <0, then P is decreasing with time
- if dP/dt = 0, then P is remaining the same with time.
The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).
c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0 and 1.
As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.
