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LiRa [457]
2 years ago
14

HELP WILL GIVE BRAINLIEST

Mathematics
1 answer:
harina [27]2 years ago
3 0

Answer:

ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

Step-by-step explanation:ccccccccccccccccccccccccccccccccccccc

ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

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Help me with A and B please
g100num [7]

Part A.

Ashwin had a 4-cm cube.

volume of cube = side^3

volume = (4 cm)^3 = 64 cm^3

Ashwin has 64 small cubes.

We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.

A. v = 2 * 4 * 7 = 28

B. v = 4 * 5 * 6 = 120

C. v = 5 * 5 * 4 = 100

D. v = 4 * 7 * 5 = 140

E. v = 3 * 5 * 4 = 60

Part A. answer: A, E

Part B.

Dora had a 5-cm cube.

volume of cube = side^3

volume = (5 cm)^3 = 125 cm^3

Dora has 125 small cubes.

We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.

A. v = 3 * 3 * 8 = 72

B. v = 3 * 4 * 5 = 60

C. v = 6 * 6 * 4 = 144

D. v = 5 * 8 * 4 = 160

E. v = 3 * 5 * 4 = 60

Part B. answer: A, B, E

6 0
3 years ago
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
2 years ago
What is the domain and range of the function?​
Ierofanga [76]

Answer:

hello dude you see um this is complicated

Step-by-step explanation:

6 0
1 year ago
Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.
algol13
Answers:
x = 24
y = 8√3
Explanation:

1) Since, the given triangle is a right triangle, and you have both an angle and the hypotenuse length, you can use some trigonometric ratios to find the variables.

2) The variables given represent:

x: adjacent-leg to angle 30°
y: opposite length to angle 30°

3) sine ratio:

sin 30° = opposite-leg / hypotenuse = y / (16√3)

⇒ y = 16√3 sin 30° = 16√3 × (1/2) = 8√3

4) cosine ratio

cos 30° = adjacent-leg / hypotenuse = x / (16√3)

⇒ x = 16√3 cos 30° = 16√3 (√3 / 2) = 16 × 3 / 2 = 24

4 0
2 years ago
According to the order of operations, which of the following operations should be completed first in the following expression?
Kamila [148]

Answer:

Step-by-step explanation:

simplify (5-3)

PEMDAS= parentheses- e -MULTIPLY- DIVIDE - ADD- SUBTRACT

2(5-3)2+62

(2*2)2+62

8+62

70

4 0
3 years ago
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