<span>Ans: I = P*r*t = 900*0.023*1.5 = $31.50
I hope this help</span>
Answer: 0.0170
Step-by-step explanation:
Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.
i.e. 

We assume the distribution of amounts purchased follows the normal distribution.
Sample size : n=50
Let
be the sample mean.
Formula : 
Then, the probability that the sample mean is at least $25.00 will be :-

Hence, the likelihood the sample mean is at least $25.00= 0.0170
Answer:
Line B - red line
Step-by-step explanation:
Not 100% sure this is right but
60cm^2
54 red cars, sorry cant explain, need points urgently, CHEERIO!