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JulijaS [17]
3 years ago
14

What is the value of x​

Mathematics
1 answer:
ZanzabumX [31]3 years ago
3 0

Umm there is no numbers

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Which expressions are equivalent to 2-(-6+3)+4c
Artyom0805 [142]

Answer:

c. none of the above

Step-by-step explanation:

(-6+3)= -3

2--3=2+3=5

5+4c cant add them since they arent like terms

final answer 5+4c and that option isnt here

3 0
2 years ago
Tính: <br> (1/27)^2016*27^2015
Alik [6]

Answer:

1/27

Step-by-step explanation:

(1/27)^2016*27^2015 =

27^-2016 * 27^2015 =

27^(-2016+2015) =

27^-1 =

1/27

6 0
2 years ago
How to wirte a linear equation from a graph
astra-53 [7]
Hey there!
I'll assume we're using the slope-intercept form equation:
y = mx + b
m = slope
b = y-intercept
First, we keep the y, because it's value depends on the x value given.
Next, we find the slope. Slope is defined as rise/run, so we take two points on the graph, find how much taller one is from another, and how far right/left they are, put those values over each other, and we have out slope (m).
Finally, we need to determine the y-intercept, and that's as simple as seeing where the line crosses the y axis and writing down that value.
Hope this helps!
8 0
3 years ago
n a survey about favorite fruits, 28 people chose apples, 17 chose oranges, and the rest chose pears. If 60 people were surveyed
nordsb [41]

Based on the number of people who chose the other fruits, the percentage of people who chose pears was <u>25%. </u>

<h3>Number of people who chose pears </h3>

= Number of participants - Number who chose apples - Number who chose oranges

= 60 - 28 - 17

= 15 people

<h3>Percentage who chose pears </h3>

= Number of people who chose pears / Total number of people x 100%

= 15 / 60 x 100%

= 25%

In conclusion, 25% chose pears.

Find out more on percentages at brainly.com/question/13516343.

7 0
2 years ago
How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
sattari [20]
<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

  cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

  (1 -sin^2(θ))cot^2(θ) =  . . . . . replace cos^2 with 1-sin^2

  cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

  cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0
3 years ago
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