You can check that
f(1)=0
f(-3)=0
f(-5)=0
thus:
f(1)=0
f(-3)=0
f(-5)=0
thus:
Student scientific calculator 3×10^5 is displayed as 3 EE 5 in that case how was the panic of 80,000 and 5000 be displayed on Th
1 answer:
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Answer: 0.052
Step-by-step explanation:
Given : The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and a standard deviation of 9.2 gigagrams per year.
i.e. and
Let x denotes the yearly amounts of carbon emissions from cars in Belgium.
Then, the probability that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 12.8 gigagrams and 14.0 gigagrams per year will be :-
Hence, the required probability = 0.052
Answer:
Bola is 8 years old.
Step-by-step explanation:
Let Bola's age be x
Dada's age be y
Ayo's age be z
If the sum of ages of Bola, Dada and Ayo is 32 years, then;
x + y + z = 32
If they share a sum of money in ratio of their ages, then the ratio of their ages will be x : y : z
Also if Bola gets N400, Dada get-N400 and Ayo get N800, then the total amount of money shared will be expressed as:
T = 400 + 400 + 800
T = N1600
Next is to get the age of Bola
Substitute the required variables and values into the formula;
This shows that Bola is 8 years old
Answer:
T = 3.967 C
Step-by-step explanation:
Density = mass / volume
Use the mass = 1kg and volume as the equation given V, we will come up with the following equation
D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3
= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1
Find the first derivative of D with respect to temperature T
dD/dT =
Let dD/dT = 0 to find the critical value we will get
= 0
Using formula of quadratic, we get the roots:
T = 79.53 and T = 3.967
Since the temperature is only between 0 and 30, pick T = 3.967
Find 2nd derivative to check whether the equation will have maximum value:
Substituting the value with T=3.967,
d2D/dT2 = -1.54 x 10^(-8) a negative value. Hence It is a maximum value
Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of
D = 1/0.001 = 1000 kg/m3
Therefore T = 3.967 C