Please help with question 7 and 8 also 9
1 answer:
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Answer:
Step-by-step explanation:
We are given the two functions:
And we want to find:
This is equivalent to:
Substitute:
Distribute:
Rearrange:
Hence:
Answer:
The endpoints of the latus rectum are and
.
Step-by-step explanation:
A parabola with vertex at point and whose axis of symmetry is parallel to the y-axis is defined by the following formula:
(1)
Where:
- Independent variable.
- Dependent variable.
- Distance from vertex to the focus.
,
- Coordinates of the vertex.
The coordinates of the focus are represented by:
(2)
The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that ,
and
, then the latus rectum is between the following endpoints:
By (2):
By (1):
There are two solutions:
Hence, the endpoints of the latus rectum are and
.
Answer:
View image
Step-by-step explanation:
You treat inequality questions just like normal equation with an equal sign. You only have to worry about the inequality when you do the shading part.
Your first goal is to solve for y, which I did at the top.
And remember that when you divide/multiply by a negative number you have to flip the inequality sign.
So the first equation is already in term of y. (y < 2x + 4)
So you only have to solve for y for -3x - 2y ≥ 6.
I solved that and got y ≤ -3/2x - 3.
Now you have 2 equations. y < 2x + 4 and y ≤ -3/2x - 3
First you gotta treat it like a normal equation and graph them.
So i graphed y = 2x + 4 and y = -3/2x - 3. I assume you already know how do do that.
btw. < and > have dotted lines, while ≤ and ≥ have solid lines.
Now for the shading, you gotta look at the inequality sign.
y < 2x + 4 has a less than sign, so you have to shade everything underneath the line you graphed.
y ≤ -3/2x - 3 is also less than, so you have to shade everything underneath that line as well.
So in the future, you you get a > or ≥ then you have to shade above the graph.
