Answer:
non liner
Step-by-step explanation:
Answer:
The desired point is thus (-1/2, -5).
Step-by-step explanation:
The x-component of this directed line segment is 2 - (-8), or 10, and the y-component is -7 - (1), or -8. This segment is in Quadrant II, since the x-component is positive and the y-component is negative.
The point of interest is (3/4) of the way in the positive x-direction from x = -8. We can express this symbolically as -8 + (3/4)(10), or -8 + 7.5, or -1/2.
The point of interest is 3/4 of the way in the negative y direction from 1, or:
1 + (3/4)(-8), or 1 - 6, or -5.
The desired point is thus (-1/2, -5).
F(x,n,p)=C(n,x)p^x*(1-p)^(n-x)
n=9, p=0.8 =>
f(x,9,0.8)=C(9,x)0.8^x*(0.2)^(9-x)
The function f(x,9,0.8) is then calculated using the above formula
x f(x)
0 0.0000001 0.0000182 0.0002953 0.0027534 0.0165155 0.0660606 0.1761617 0.3019908 0.3019909 0.134218
Check Sum f(x), [x=0,9] = 1.0 ok
we have M is durectly porpotional to r^2
so M=(k)r^2
and when r=2, m=14
so 14=(k)(2)^2
k=14/4 =7/2
so when r=12
m= (7/2)(12)^2 =(7/2)(144) = 504
