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3 years ago

FREE BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!! (I CAN TELL I YOU LIE)

Mathematics

1 answer:

enyata [817]3 years ago

4 0

Answer:

Ermmm, theres no table/graph so maybe try repostin?

Step-by-step explanation:

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f of x equals 4 x over quantity x squared minus 16. Show all work to identify the asymptotes and zero of the function.

yuradex [85]

Given:

The function is

$f(x)=\dfrac{4x}{x^2-16}$

To find:

The asymptotes and zero of the function.

Solution:

We have,

$f(x)=\dfrac{4x}{x^2-16}$

For zeroes, f(x)=0.

$\dfrac{4x}{x^2-16}=0$

$4x=0$

$x=0$

Therefore, zero of the function is 0.

For vertical asymptote equate the denominator of the function equal to 0.

$x^2-16=0$

$x^2=16$

Taking square root on both sides, we get

$x=\pm \sqrt{16}$

$x=\pm 4$

So, vertical asymptotes are x=-4 and x=4.

Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.

8 0

3 years ago

Find the total number of diagonals in a regular nonagon.

anastassius [24]

Answer:

Step-by-step explanation:

number of diagonals in a regular polygon = number of sides - 2.

A nonagon is a polygon having 9 sides.

Total number of diagonals in a regular nonagon

= 9 - 2

= 7

3 0

3 years ago

Consider the function. What is the y-intercept of f–1(x)? –16 –12

Mekhanik [1.2K]

<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write clear questions in order to get good and exact answers. Here, I'll assume the function as:

$f(x)=x^2+2x-16$

The y-intercept of a function is the point at which the graph of the function touches the y-axis. This occurs when we set $x=0$ . In other words, we define the y-intercept (let's call it $b$ as:

$b=f(0)$

Setting $x=0$ in our function we have:

$b=f(0)=(0)^2+2(0)-16 \\ \\ \boxed{b=f(0)=-16}$

So <em>in this context the y-intercept is -16</em>

7 0

3 years ago

3,4,4,5,5,6,6,6,6,7,9,12,14,15 Min: Q1: Med: Q3: Max:

kolezko [41]

Answer:

Median ( Q2) = 6

Q1 ( lower quartile) = 4.5

Q3 ( upper quaartile) = 10.5

Step-by-step explanation:

<u>3,4,4,5,5,6, </u>6,6 ,<u>6,7,9,12,14,15</u>

6,6 is the median but we only need I median. So 6 + 6 = 12, 12 divided 2 = 6.

3,4,<u>4,5,</u>5,6, is the Q1 ( lower quartile ) and median of Q1, is 4,5. 4 + 5 = 9. 9 divided 2 = 4.5

6,7,<u>9,12,</u>14,15 is Q3 ( upper quartile) 9,12 is median but we only need one. So 9 + 12 =21. 21 divided 2 = 10.5

5 0

2 years ago

For a parabola with a minimum point at (3,-1), determine the equation for the function's axis of symmetry

algol [13]

Answer:

x=3

(Do not write a character less than what I have written; 3 is not the answer but x=3 is the answer.)

Step-by-step explanation:

Parabolas have a axis of symmetry; this is the line they are symmetrical about.

The line of symmetry will always go through the vertex.

Since your question says it is a function the line will be vertical and will be of the form x=a number.

The number is determine by the x-coordinate of the vertex.

I know the vertex of your problem is (3,-1) because it says that is the minimum point of the graph. The vertex of a parabola will always be it's maximum (this parabola is open down) or minimum (this parabola is open up).

So the axis of symmetry is just:

x=3.

You must actually write x=3.

3 is not the answer.

x=3 is the answer.

Little note down here:

(If it had said the parabola wasn't a function, the axis of symmetry would have been horizontal and therefore of the form y=a number where the number was the y-coordinate of the vertex.)

8 0

3 years ago

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