Question

Consider the function. What is the y-intercept of f–1(x)? –16 –12

Answer 1

Explanation:

Hello! Remember you have to write clear questions in order to get good and exact answers. Here, I'll assume the function as:

$f(x)=x^2+2x-16$

The y-intercept of a function is the point at which the graph of the function touches the y-axis. This occurs when we set $x=0$. In other words, we define the y-intercept (let's call it $b$ as:

$b=f(0)$

Setting $x=0$ in our function we have:

$b=f(0)=(0)^2+2(0)-16 \\ \\ \boxed{b=f(0)=-16}$

So in this context the y-intercept is -16