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Marat540 [252]
3 years ago
14

Which symbols correctly relate the two numbers?

Mathematics
1 answer:
geniusboy [140]3 years ago
4 0
I can see the numbers
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6.<br> Find the area of a rectangle with<br> length 2x - 7 and width 3x +4.
alekssr [168]

Answer:

A=6x^{2} -13x-28

Step-by-step explanation:

A=L(W)

A=2x-7(3x+4)

Use distributive property

A=6x^{2} +8x-21x-28

Combine like terms

A=6x^{2} -13x-28

6 0
3 years ago
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5x + 2y = 8
stich3 [128]
The answer should be c.
3 0
3 years ago
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Solve the inequality 5x - 7 ≤ 32​
svetlana [45]

Answer:

x ≤ 39/5

Step-by-step explanation:

To solve for the inequality, isolate the x variable.

5x - 7 ≤ 32​

Add 7 to both sides.

5x ≤ 39

Divide both sides by 5.

x ≤ 39/5

4 0
3 years ago
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If you predict the population of Hamilton County in 2003, are you interpolating or extrapolating?
Hitman42 [59]

Given,

The population of the county in 2000 is 844.

The population of the county in 2009 is 856.

The population of the county in 2015 is 810.

Here, the population of 2000 and 2009 is given.

As known, the value changes linearly between two points.

When the value changes linearly between two points, then value of point between given points can be obtained by interpolation.

Hence, to predict the population of county interpolation is used.

5 0
1 year ago
For what values of a and b are x+1 and x+2 factors of x3 – ax2 – bx –8? Write down the other factor.
emmainna [20.7K]
<h2>For a = 1 and b = 10 x+1 and x+2 factors of  x³-ax²-bx-8 = 0</h2><h2>Other factor is (x-4)</h2>

Step-by-step explanation:

We have

                 x³-ax²-bx-8 = 0

Its factors are x+1 and x+2

That is x = -1 and x = -2 are its roots

Substituting x = -1

               (-1)³-a(-1)²-b(-1)-8 = 0

                -1 - a + b - 8 = 0

                      b - a = 9 ---------------------eqn 1

Substituting x = -2

               (-2)³-a(-2)²-b(-2)-8 = 0

                -8 - 4a + 2b - 8 = 0

                      2b - 4a = 16 ---------------------eqn 2

eqn 1 x -2

                      -2b + 2a = -18 ---------------------eqn 3

eqn 2 + eqn 3

                      -2a = -2

                          a = 1

Substituting in eqn 1

                        b - 1 = 9

                         b = 10

For a = 1 and b = 10,  x+1 and x+2 factors of  x³-ax²-bx-8 = 0

The equation is  x³-x²-10x-8 = 0

Dividing with x + 1 we will get

                   x³-x²-10x-8 = (x+1)(x²-2x-8)

Dividing (x²-2x-8) with x + 2 we will get

                  x²-2x-8 = (x+2)(x-4)

So we have

               x³-x²-10x-8 = (x+1)(x+2)(x-4)

Other factor is (x-4)

8 0
3 years ago
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