Y^2/2560x^12z^14........................................
The answer is -202
Hope this helps! :)
Answer: p = 30 q = 30 (if not touching edge of hexagon but if it is touching edge one of the pairs) then p or q = 120 and p and q = 30
Step 1) Sum of an interior angle of a polygon = 720 degree where n = 6 as 6 exterior sides = (n-2) * 180 = (6-2) * 180 = 4 * 180 = 720 degree Where the measure of each angle of a hexagon = 720/ 6 = 120 degree Step 2) Then show 3 angle letter names = 180 degree Step 3) Angle name letters + 2 angle (other two names letters inside within triangle) add up to 180 degree Step 3) State since triangle name (of all letters within one triangle) is Isosceles Step 4) <u>Triangle (state same triangle letters with number 2 in front) = 180 - 120 = 60 then state triangle (letter name) / 2 = 30 degrees </u>obviously the 120 and 60 differentiates if not a hexagon to a pentagon if not a hexagon = (3 *180) / 5 = 108 then due to isosceles (180 - 108)/ 2 = 72/2 = 36 degree for a p<u>entagon </u>or 30 degree each for p + q for a <u>hexagon</u> etc
Answer:
The Law of Cosine : cos C = 
Step-by-step explanation:
See the figure to understand the proof :
Let A Triangle ABC with sides a,b,c,
Draw a perpendicular on base AC of height H meet at point D
Divide base length b as AD = x -b and CD = x
By Pythagoras Theorem
In Triangle BDC And In Triangle BDA
a² = h² + x² ( 1 ) c² = h² + (x-b)²
c² = h² + x² + b² - 2xb ...(. 2)
From above eq 1 and 2
c² = (a² - x²) + x² + b² - 2xb
or, c² = a² + b² - 2xb .....(3)
Again in ΔBDC
cos C = 
Or, cos C = 
∴ x= a cos C
Now put ht value of x in eq 3
I.e, c² = a² + b² - 2ab cos C
Hence , cos C = Proved Answer
Answer:
see explanation
Step-by-step explanation:
A rational number can be expressed in the form
← where a and b are integers
An example is
- 5 can be expressed as 
and is therefore rational
Numbers which are not rational are irrational
π and 
are examples of irrational numbers
