<span>a. What is the probability that the printer produces more than 12,000 pages before this cartridge must be replaced?
solution
to solve the equation we need to find the z-score:
z=(x-</span>μ)/σ
where:
x=12000
μ=mean=11500
σ=standard deviation=800
thus
z=(12000-11500)/800=0.625
thus
P(x>12000)=1-P(x<12000)=1-0.7357=0.2643
<span>b. What is the probability that the printer produces fewer than 10,000 pages?
z=(10000-11500)/800
z=-1.875
hence
P(x<10000)
=0.0301
</span>
Answer: b =27
Step-by-step explanation:
24 = b -3 Just add 3 to both sides
+3 +3
b = 27
Answer:
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Step-by-step explanation:
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