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DENIUS [597]
3 years ago
14

Use any order, any grouping to write an equivalent expression: 3(2x) + 4y(5) + (4 x 2 x z)

Mathematics
1 answer:
enyata [817]3 years ago
8 0

Answer:

We conclude that the equivalent expression is:

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z

Step-by-step explanation:

Given the expression

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)

Remove parentheses: (a) = a

=3\times \:2x+4\times \:5y+4\times \:2z

Multiply the numbers: 3 ×  2 = 6

=6x+4\times \:5y+4\times \:2z

Multiply the numbers: 4 × 5 = 20

=6x+20y+4\times \:2z

Multiply the numbers: 4 × 2 = 8

=6x+20y+8z

Thus, we conclude that the equivalent expression is:

3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z

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A. Measure of angle A + measure of angle B

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The mean time it takes to walk to the bus stop is 8 minutes (with a standard deviation of 2 minutes) and the mean time it takes
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(a) Average time to get to school
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(b) Standard deviation of the whole trip to school
Standard deviation for the whole trip = Sqrt (Summation of variances)

Variance = Standard deviation ^2
Therefore,
Standard deviation for the whole trip = Sqrt (2^2+4^2) = Sqrt (20) = 4.47 minutes

(c) Probability that it will take more than 30 minutes to get to school
P(x>30) = 1-P(x=30)
Z(x=30) = (mean-30)/SD = (28-30)/4.47 ≈ -0.45
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Therefore,
P(X>30) = 1-P(X=30) = 1-0.3264 = 0.6736 = 67.36%

With actual average time to walk to the bus stop being 10 minutes;

(d) Average time to get to school
Actual average time to get to school = 10+20 = 30 minutes

(e) Standard deviation to get to school
Actual standard deviation = Previous standard deviation = 4.47 minutes. This is due to the fact that there are no changes with individual standard deviations.

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From Z table, P(x=30) = 0.5
And therefore, P(x>30) = 1- P(X=30) = 1- P(Z=0.0) = 1-0.5 = 0.5 = 50%
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