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2 years ago

Find mABC A-54 B-135 C-15 D-126

Mathematics

1 answer:

bagirrra123 [75]2 years ago

7 0

It’s B

Glad I could help

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Find the value of x in the equation below. 3x = 18

Oxana [17]

Answer:

x=6

Step-by-step explanation:

you need to get x alone so you divide by 3 on both sides

hope this helps!!! :)

example:

3x/3= 18/3

x=6

4 0

2 years ago

Read 2 more answers

Complete the equation of the line through (-9,-9) and (-6,0)

Rudik [331]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis.

According to the data of the statement we have the following points:

$(x_ {1}, y_ {1}): (- 9, -9)\\(x_ {2}, y_ {2}): (- 6,0)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0 - (- 9)} {- 6 - (- 9)} = \frac { 9} {- 6 + 9} = \frac {9} {3} = 3$

Thus, the equation is of the form:

$y = 3x + b$

We substitute one of the points and find b:

$0 = 3 (-6) + b\\0 = -18 + b\\b = 18$

Finally, the equation is:

$y = 3x + 18$

Answer:

$y = 3x + 18$

7 0

3 years ago

Pre cacl pleaseeeee help. the options are in the attachments as well

ivanzaharov [21]

Answer:

The values of $x$ so that $y = \csc x$ have vertical asymptotes are $-2\pi$ , $-\pi$ , $0$ , $\pi$ , $2\pi$ .

Step-by-step explanation:

The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of $x$ so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is $\pi$ . Then, the vertical asymptotes associated with function cosecant are located in the values of $x$ of the form:

$x = 0\pm \pi\cdot i$ , $\forall \,i\in \mathbb{N}_{O}$