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Marizza181 [45]
3 years ago
15

PROBLEM Convert 147% to a fraction in simplest form. I’m

Mathematics
2 answers:
Charra [1.4K]3 years ago
5 0

Answer:

1 \frac{47}{100}

Step-by-step explanation:

147% as a fraction would be 147/100. since we need to put it in simplest form, the answer would be 1 \frac{47}{100}

ladessa [460]3 years ago
4 0

Answer:

147/100

Step-by-step explanation:

This is the simplest form it can be placed in! It cannot be simplified any further whatsoever.

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Compare the functions shown below:<br><br> Which function has the greatest maximum y-value?
solmaris [256]
Answer: It's a tie between f(x) and h(x). Both have the same max of y = 3

The highest point shown on the graph of f(x) is at (x,y) = (pi,3). The y value here is y = 3.

For h(x), the max occurs when cosine is at its largest: when cos(x) = 1. 
So,
h(x) = 2*cos(x)+1
turns into
h(x) = 2*1+1
h(x) = 2+1
h(x) = 3
showing that h(x) maxes out at y = 3 as well

--------------------------------

Note: g(x) has all of its y values smaller than 0, so there's no way it can have a max y value larger than y = 3. See the attached image to see what this graph would look like if you plotted the 7 points. A parabola seems to form. Note how point D = (-3, -2) is the highest point for g(x). So the max for g(x) is y = -2

3 0
3 years ago
Read 2 more answers
In Circle P, m EA=58, m BC=42, m CD=90, find:
elena55 [62]

Circle theorem states that the angle that an arc subtends at the center of a

circle is twice the angle subtended at the circumference.

The values are as follows;

  1. m∠EDA = <u>90°</u>
  2. m∠BDC = <u>21°</u>
  3. m∠BEC = <u>21°</u>
  4. m\widehat{AB} =<u> 80°</u>
  5. m∠AEB = <u>40°</u>
  6. m∠ECA =  <u>29°</u>
  7. m∠BAC = <u> 21°</u>
  8. <u />m\widehat{ED}  =  <u>90°</u>
  9. m∠ECD = <u>45°</u>
  10. m∠ACB = <u>40°</u>
  11. m∠EBD = <u>45°</u>
  12. m∠ADB = <u>40°</u>
  13. m∠CAD = <u>45°</u>
  14. m∠EAB = <u>90°</u>
  15. m∠EBC = <u>90°</u>

<u />

Reasons:

\displaystyle 1. \ \mathbf{m\angle EDA} = \frac{1}{2} \cdot m\angle EPC Angle subtended at center is twice angle at circumference.

m∠EPC = 180°

∴  m∠EDA = 0.5 × 180° = <u>90°</u>

2. m\widehat{BC} = 42°, therefore, m∠BPC = 42°

\displaystyle \ m\angle BDC= \frac{1}{2} \cdot m\angle BPC

m∠BDC = 0.5 × 42° =<u> 21°</u>

3. m∠BEC = m∠BDC = <u>21°</u>

4. m\widehat{AB} = 180° - (58° + 42°) =<u> 80°</u>

5. \mathbf{m\widehat{AB}} = m∠APB by definition

m∠AEB = 0.5 × m∠APB

m∠AEB = 0.5 × 80° = <u>40°</u>

6. m∠ECA = 0.5 × m∠AE

Therefore;

m∠ECA = 0.5 × m\widehat{EA}

m∠ECA = 0.5 × 58° = 29°

m∠ECA =  <u>29°</u>

7. m∠BAC = 0.5 × \mathbf{m\widehat{BC}}

m∠BAC = 0.5 × 42° = 21°

m∠BAC = <u> 21°</u>

8. m\widehat{ED}  = 180° - \mathbf{m\widehat{CD}}

m\widehat{ED}  = 180° - 90° = 90°

\mathbf{m\widehat{ED}}  =  <u>90°</u>

9. m∠ECD = 0.5 × \mathbf{m\widehat{ED}}

m∠ECD = 0.5 × 90° = <u>45°</u>

10. m∠ACB = 0.5 × m\widehat{AB}

m∠ACB = 0.5 × 80° = <u>40°</u>

11. m∠EBD = 0.5 × \mathbf{m\widehat{ED}}

m∠EBD = 0.5 × 90° = <u>45°</u>

12. m∠ADB = 0.5 × \mathbf{m\widehat{AB}}

m∠ADB = 0.5 × 80° = <u>40°</u>

13. m∠CAD = 0.5 × \mathbf{m\widehat{CD}}

m∠CAD = 0.5 × 90° = <u>45°</u>

14. m∠EAB = 0.5 ×\mathbf{m\widehat{EABC}}

m∠EAB = 0.5 × 180° = <u>90°</u>

15. m∠EBC = 0.5 ×\mathbf{m\widehat{EABC}}

m∠EBC = 0.5 × 180° = <u>90°</u>

<u />

<u />

Learn more about circle theorems here:

brainly.com/question/25101481

3 0
3 years ago
Lisa took a survey of her classmates' favorite sport and recorded their genders. The results are in the table below:
Igoryamba

Answer:

0.43

17

Step-by-step explanation:

8 0
3 years ago
Multiply −3x2(6x2 + 2x − 3).
mr_godi [17]

Answer:

hope this will help you.

7 0
3 years ago
Finding the average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11
krok68 [10]

Answer:

The average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11) is 0.

Step-by-step explanation:

Given a function y, the average rate of change S of y=g(z) in an interval  (z_{s}, z_{f}) will be given by the following equation:

S = \frac{g(z_{f}) - g(z_{s})}{z_{f} - z_{s}}

In this problem, we have that:

g(z) = 4z^{2} - 5

Between the points( -2,11) and (2,11).

So z_{f} = 2, z_{s} = -2

g(z_{f}) = g(2) = 4*(2)^{2} - 5 = 11

g(z_{s}) = g(-2) = 4*(-2)^{2} - 5 = 11

So

S = \frac{g(z_{f}) - g(z_{s})}{z_{f} - z_{s}} = \frac{11 - 11}{2 - (-2)} = \frac{0}{4} = 0

The average rate of change of g(z) =4x^2_5 between the points( -2,11) and (2,11) is 0.

3 0
3 years ago
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