Answer:

Step-by-step explanation:
Given

Required
Approximate (to the nearest 100th)
This means that, we approximate at the second digit after the decimal.
So:
i.e,
Number = 39.79 [Begin approximation] 949748
The first digit after [Begin approximation] is then approximated using the following rule:


Since 9 falls in
category, the number becomes:
![Number = 39.[79+1]](https://tex.z-dn.net/?f=Number%20%3D%2039.%5B79%2B1%5D)

To find the circumference, you would use 2πr.
Answer:
2*π*16
=100.53in^2
1/3(9x) =3x
1/3(18) =6
3x+6-5
Then you do
-(x)=-x
-(3)=-3
5x-x-3 = 4x-3
4x-3=3x+6-5
4x-3=3x+1
x=4
132, if you add four to 50, and keep going until you get to 20