Miguel Cabrera had a batting average of 0.33 last season.Mike trout had a batting average of 0.326 during the same season. Who h
ad the higher batting average
1 answer:
Answer:
Miguel cabrera
Step-by-step explanation:
Given that :
Miguel cabrera's batting average = 0.33
Mike trout's batting average = 0.326
The average for both players was obtained during the same season:
Hence. Comparing their respective averages,
0.33 = 0.330
0.330 > 0.326
Hence, Miguel Cabrera's batting average is higher than that of Mike trout
You might be interested in
Answer:
41 units
Step-by-step explanation:
Pythagorean's theorem,
Hypotenuse² = base² + adjacent²
Diagonal² = length² + width²
= 40² + 9²
= 1600 + 81 = 1681
Diagonal = √1681 = 41 units
Answer:
B
Step-by-step explanation:
He also is a point guard and has shoe game.
I would say B because of KAO keep add opposite.
Answer:
1. 4.25
2. 8.75
3. 8
Step-by-step explanation:
Consecutive integers are −11 times -9 or 11 times 9